A 0.2422 g sample of a certain fruit was analyzed for the content of a certain pesticide. After a series of extraction steps, the final extract obtained was diluted to 10.00 mL, which was then subjected to chromatographic analysis. Four standard solutions of the pesticide were also prepared, processed, and
A 0.2422 g sample of a certain fruit was analyzed for the content of a certain pesticide. After a series of extraction steps, the final extract obtained was diluted to 10.00 mL, which was then subjected to chromatographic analysis. Four standard solutions of the pesticide were also prepared, processed, and
Chapter14: Chromatography
Section: Chapter Questions
Problem 9P
Related questions
Question
![1. What's the slope of the calibration curve?
3.95x 10-5
4.17x10-5
20484
25257
What's the y-intercept value?
-114.3
-0.0137
0.00471
583.1
3. What's the concentration of the analyte in the sample solution?
2.39x 10-8 µg/mL
0.070 µg/mL
0.052 ug/mL
3.97x 107 µg/mL
4.19x107 µg/mL
What is the concentration of the pesticide in the sample (ppm)?
0.52 ppm
0.70 ppm
0.99 ppm
2.2 ppm
2.9 ppm](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8dd5ecd4-9d74-4d0a-a174-44f6ad2c456d%2F73201da3-a435-470d-af44-bbdc3d361b00%2F2mdtl0s_processed.png&w=3840&q=75)
Transcribed Image Text:1. What's the slope of the calibration curve?
3.95x 10-5
4.17x10-5
20484
25257
What's the y-intercept value?
-114.3
-0.0137
0.00471
583.1
3. What's the concentration of the analyte in the sample solution?
2.39x 10-8 µg/mL
0.070 µg/mL
0.052 ug/mL
3.97x 107 µg/mL
4.19x107 µg/mL
What is the concentration of the pesticide in the sample (ppm)?
0.52 ppm
0.70 ppm
0.99 ppm
2.2 ppm
2.9 ppm
![A 0.2422 g sample of a certain fruit was analyzed for the content of a certain pesticide. After a series of
extraction steps, the final extract obtained was diluted to 10.00 mL, which was then subjected to
chromatographic analysis. Four standard solutions of the pesticide were also prepared, processed, and
analyzed in the same manner. The data obtained are shown in the table below.
Solution
Concentration (µg/mL)
Peak Area
Standard 1
0.01
234.2
Standard 2
0.05
1101.2
Standard 3
0.10
2300.1
Standard 4
0.20
4999.8
Sample
?
1654.3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8dd5ecd4-9d74-4d0a-a174-44f6ad2c456d%2F73201da3-a435-470d-af44-bbdc3d361b00%2F7ru5r9_processed.png&w=3840&q=75)
Transcribed Image Text:A 0.2422 g sample of a certain fruit was analyzed for the content of a certain pesticide. After a series of
extraction steps, the final extract obtained was diluted to 10.00 mL, which was then subjected to
chromatographic analysis. Four standard solutions of the pesticide were also prepared, processed, and
analyzed in the same manner. The data obtained are shown in the table below.
Solution
Concentration (µg/mL)
Peak Area
Standard 1
0.01
234.2
Standard 2
0.05
1101.2
Standard 3
0.10
2300.1
Standard 4
0.20
4999.8
Sample
?
1654.3
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