A 0.194-g sample of a nonvolatile solid solute dissolves in 9.82 g of cyclohexane. The change in the freezing point of the solution is 2.94°C. (Kf of Cyclohexane is 20.0°C/m) A)What is the molality of the
A 0.194-g sample of a nonvolatile solid solute dissolves in 9.82 g of cyclohexane. The change in the freezing point of the solution is 2.94°C. (Kf of Cyclohexane is 20.0°C/m)
A)What is the molality of the solute in the solution?
B)Calculate the molar mass of the solute to the correct number of significant figures.
C)The same mass of solute is dissolved in 9.82 g of TBA instead of cyclohexane. (Kf of TBA is 9.1°C/m) What is the expected freezing point?
The question is based on the concept of solutions.
depression is freezing point is a colligative property. on adding solute to the solvent, freezing point of the solution is depressed than the freezing point of solvent.
this is because now more amount of cooling is required to freeze the solution. as unlike interaction exist between solute and solvent which are difficult to break.
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