A 0.10 µM aqueous solution of a metal ion, M²+, is extracted into an organic solvent by 0.19 mM of the ligand L. Given that KL = 1.6 x 10“, KM = 5.0 × 10*, Ka 2.0 x 10-5, B, = 2.0 x 1022, and n = 2, calculate the distribution ratio, D, for the extraction at pH 2.50 and at pH 6.00. DpH=2.50 = DpH=6.00 Calculate the fraction of M2+ that remains in the aqueous phase, q, if 135 mL of 0.10 µM M²+ is extracted once with 10.0 mL of 0.19 mM L¯ at pH 2.50. 9pH=2.50 =
A 0.10 µM aqueous solution of a metal ion, M²+, is extracted into an organic solvent by 0.19 mM of the ligand L. Given that KL = 1.6 x 10“, KM = 5.0 × 10*, Ka 2.0 x 10-5, B, = 2.0 x 1022, and n = 2, calculate the distribution ratio, D, for the extraction at pH 2.50 and at pH 6.00. DpH=2.50 = DpH=6.00 Calculate the fraction of M2+ that remains in the aqueous phase, q, if 135 mL of 0.10 µM M²+ is extracted once with 10.0 mL of 0.19 mM L¯ at pH 2.50. 9pH=2.50 =
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:A 0.10 µM aqueous solution of a metal ion, M²+, is extracted into an organic solvent by 0.19 mM of the ligand L¯. Given that
= 5.0 x 10*, K, = 2.0 x 10-, Br = 2.0 x 1022, and n = 2, calculate the distribution ratio, D, for the
KL
3D 1.6 х 10*, Км
extraction at pH 2.50 and at pH 6.00.
DpH=2.50 =
DpH=6.00 =
Calculate the fraction of M+ that remains in the aqueous phase, q, if 135 mL of 0.10 µM M²+ is extracted once with 10.0 mL
of 0.19 mM L¯ at pH 2.50.
9pH=2.50 =
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