- 9t & y =-8s - 6t. у дх ду 's' at Ət and using the chain rule.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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t3

**Problem Statement:**

Let \( z(x, y) = -4x^2 + 3y^2 \) where \( x = -s - 9t \) and \( y = -8s - 6t \).

**Task:**

Calculate \(\frac{\partial z}{\partial s}\) and \(\frac{\partial z}{\partial t}\) by first finding:

- \(\frac{\partial x}{\partial s}\), \(\frac{\partial y}{\partial s}\)
- \(\frac{\partial x}{\partial t}\), \(\frac{\partial y}{\partial t}\)

and using the chain rule.

**Expressions to Find:**

\[
\frac{\partial z}{\partial s} = \text{(Use this space for your answer)}
\]

\[
\frac{\partial z}{\partial t} = \text{(Use this space for your answer)}
\]

**Instructions:**

- Determine the partial derivatives of \( x \) and \( y \) with respect to \( s \) and \( t \).
- Apply the chain rule to find \(\frac{\partial z}{\partial s}\) and \(\frac{\partial z}{\partial t}\).
Transcribed Image Text:**Problem Statement:** Let \( z(x, y) = -4x^2 + 3y^2 \) where \( x = -s - 9t \) and \( y = -8s - 6t \). **Task:** Calculate \(\frac{\partial z}{\partial s}\) and \(\frac{\partial z}{\partial t}\) by first finding: - \(\frac{\partial x}{\partial s}\), \(\frac{\partial y}{\partial s}\) - \(\frac{\partial x}{\partial t}\), \(\frac{\partial y}{\partial t}\) and using the chain rule. **Expressions to Find:** \[ \frac{\partial z}{\partial s} = \text{(Use this space for your answer)} \] \[ \frac{\partial z}{\partial t} = \text{(Use this space for your answer)} \] **Instructions:** - Determine the partial derivatives of \( x \) and \( y \) with respect to \( s \) and \( t \). - Apply the chain rule to find \(\frac{\partial z}{\partial s}\) and \(\frac{\partial z}{\partial t}\).
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