9csc²x-23 = -cscx+3 cot²x-6 sinx A) Simplify the equation, such that it resembles a quadratic function. B) Determine the value(s) of "x" that satisfie(s) the equation. Assume 0 ≤ x ≤ 360°. (***Note: If you're having trouble simplifying the above equation, then assume this equation 2sec²x-secx - 6 = 0.***) (***Hint: Look for primary ratios that can be applied to a CAST diagram; drawing a simple sketch could further help visualize the solution.***)

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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Show each step with clear writing and write in 2 sentences the conclusion of what you did and how you got the answer .
2. Here is an equation:
9csc²x - 23=-cscx + 3cot²x -
6
sinx
A) Simplify the equation, such that it resembles a quadratic function.
B) Determine the value(s) of "x" that satisfie(s) the equation.
Assume 0 ≤ x ≤ 360°.
(***Note: If you're having trouble simplifying the above equation, then
assume this equation 2sec²x-secx - 6 = 0.***)
(***Hint: Look for primary ratios that can be applied to a CAST
diagram; drawing a simple sketch could further help visualize the
solution.***)
Transcribed Image Text:2. Here is an equation: 9csc²x - 23=-cscx + 3cot²x - 6 sinx A) Simplify the equation, such that it resembles a quadratic function. B) Determine the value(s) of "x" that satisfie(s) the equation. Assume 0 ≤ x ≤ 360°. (***Note: If you're having trouble simplifying the above equation, then assume this equation 2sec²x-secx - 6 = 0.***) (***Hint: Look for primary ratios that can be applied to a CAST diagram; drawing a simple sketch could further help visualize the solution.***)
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