An ESP is to he designed to treat 9000 m3/min of gas to remove particles at 99.8% efficiency. Using Figure 5.10, estimate the required corona power in kW. 99.999.899.799.599.399.098979593100200300400500600Corona power ratio, W/1000 acfmFigure 5.10Collection efficiency as a function of corona power ratio, based on actual data.(Adapted from White, 1984.)Collection efficiency, %

Given values: Q = 9000 m3/min Efficiency = 99.8 % Consider graph in Fig.5.10.

Answered: 99.9 99.8 99.7 99.5 99.3 99.0 98 97 95…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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An ESP is to he designed to treat 9000 m³/min of gas to remove particles at 99.8% efficiency. Using Figure 5.10, estimate the required corona power in kW.

99.9
99.8
99.7
99.5
99.3
99.0
98
97
95
93
100
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500
600
Corona power ratio, W/1000 acfm
Figure 5.10
Collection efficiency as a function of corona power ratio, based on actual data.
(Adapted from White, 1984.)
Collection efficiency, %

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