99. Wind engineers have found that wind speed v (in meters per second) at a given location follows a Rayleigh distribution of the type W (v) = -²/64 ve 32 This means that at a given moment in time, the probability that v lies between a and b is equal to the shaded area in Figure 4. (a) Show that the probability that v e [0, b] is 1 – e-b²/64 (b) Calculate the probability that v e [2, 5]. 00.1- y= W(1) 0.05- v (m/s) 20 FIGURE 4 The shaded area is the probability that v lies between a and b.
99. Wind engineers have found that wind speed v (in meters per second) at a given location follows a Rayleigh distribution of the type W (v) = -²/64 ve 32 This means that at a given moment in time, the probability that v lies between a and b is equal to the shaded area in Figure 4. (a) Show that the probability that v e [0, b] is 1 – e-b²/64 (b) Calculate the probability that v e [2, 5]. 00.1- y= W(1) 0.05- v (m/s) 20 FIGURE 4 The shaded area is the probability that v lies between a and b.
Calculus: Early Transcendentals
8th Edition
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
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![99. Wind engineers have found that wind speed v (in meters per second) at a given location follows a
Rayleigh distribution of the type
W (v) =
-²/64
ve
32
This means that at a given moment in time, the probability that v lies between a and b is equal to the shaded
area in Figure 4.
(a) Show that the probability that v e [0, b] is 1 – e-b²/64
(b) Calculate the probability that v e [2, 5].
00.1-
y= W(1)
0.05-
v (m/s)
20
FIGURE 4 The shaded area is the probability that v lies between a and b.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe91bc59a-28f9-4852-9472-c8f52223715b%2Fff8093ae-bffb-4f77-8c53-3dd0c2d59a8b%2Fh7d9d9.png&w=3840&q=75)
Transcribed Image Text:99. Wind engineers have found that wind speed v (in meters per second) at a given location follows a
Rayleigh distribution of the type
W (v) =
-²/64
ve
32
This means that at a given moment in time, the probability that v lies between a and b is equal to the shaded
area in Figure 4.
(a) Show that the probability that v e [0, b] is 1 – e-b²/64
(b) Calculate the probability that v e [2, 5].
00.1-
y= W(1)
0.05-
v (m/s)
20
FIGURE 4 The shaded area is the probability that v lies between a and b.
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