-98% confidence interval for uis a. 49.80 to 50.20. b. 38.55 to 41.45. c. 48.64 to 51.36. d. 40.2 to 59.8.

Q: If the Za/2= 1.56, find the percent (nearest whole number,  for the confidence interval

A: Here, Za/2=1.56. Procedure for finding the percent value corresponding to 1.56 from standard normal…

Q: (1 point) Listed below are the lenths (in minutes) of randomly selected music CDs. Construct a 99%…

A:

Q: The mean scores of a random sample of 17 students who took a special test is 83.5. If the standard…

A: Given;sample size(n)=17sample mean(x¯)=83.5sample s.d.(s)=4.1for confidence level 95%, significance…

Q: Q3: A researcher believes the average IQ of adults is change. A random sample of 5 adults ested and…

A:

Q: The average salary of 64 employee was 5400. Using historical data, we will assume that the…

A: Given,sample size(n)=64mean(X¯)=5400standard deviation(σ)=260α=1-0.95=0.05α2=0.025Z0.025=1.96…

Q: Construct a confidence interval for the mean of the paired differences for the two populations with…

A: Solution: From the given information, n=32, d-bar=1.358, α=0.05 and sd=0.635.

Q: The random sample is 100 students 16 to 22 years old. The mean of hours they sleep is 8.9 hrs and…

A: Given,sample size(n)=100mean(μ)=8.9standard deviation(s)=2.2α=1-0.95=0.05α2=0.025degrees of…

Q: A random sample of 115 light bulbs had a mean life of x = 507 hours. Assume that o = 32 hours.…

A: Given  Sample size=n=115, sample mean x̄=507, standard deviations σ=32  Construct 90% CI for…

Q: The grade point averages for a sample of 10 randomly selected junior college students have an…

A:

Q: ta 99% confidence interval for the mean number of hours a student studies per week. Assume that the…

A: We are going to find 99% confidence interval by finding the critical value

Q: Find the 2-decimal answers for a 96% confidence interval if a samle of 56 students have a mean…

A: From the provided information, Population standard deviation (σ) = 2.35 Sample mean (x̄) = 51 Sample…

Q: A professor wants to estimate how many hours per week her students study. A simple random sample of…

A: Sample size Sample mean Confidence level is 99% i.e., 0.99.Population standard deviation

Q: for 97% confidence interval is 1.88 2.17 1.65 1.96

A:

Q: what would the 95% confidence limits for a sample of 120 with a mean of 51 and a standard deviation…

A: It is given that mean and standard deviation are 51 and 12, respectively.

Q: Find the value of za/2 that corresponds to a confidence level of 89.48%.

A: Confidence level: C=0.8948

Q: i need help with the upper 95% confidence interval of the difference

A: We have given the sample mean of difference of scores   X̅=-1.60  with standard deviations  s=1.1402…

Q: A sample of 14 commuters in Cebu showed the average of the commuting times was 33.2 minutes. If the…

A: Sample size : n=14 Sample mean : x¯=33.2 Sample standard deviation : s=8.3 Confidence level :…

Q: A sample of 10 adult elephants had an average weight of 12,881 pounds. The standard deviation for…

A: Given,sample size(n)=10sample mean(x)=12881standard deviation(s)=27degrees of…

Q: Form a 90% confidence interval on the difference in the means. population std dev group mean 6.

A: Given,    Group n Mean Population standard  deviation 1 30 20.5 1.5 2 30 14.5 1.5

Q: Find Ta/2 for a 90% confidence interval and a sample size of 30.

A: 90% confidencve inetrval for Sample size : n = 30Critical value of T = ?

Q: You may need to use the appropriate appendix table or technology to answer this question. Sales…

A:

Q: Construct a 99% confidence interval for the true average number of visitors per day to a fun park,…

A: Obtain the 99% confidence interval for the true average number of visitors per day to a fun work.…

Q: A fitness center is interested in finding a 98% confidence interval for the mean number of days per…

A:

Q: Suppose the mean height in inches of all 9th grade students at one high school is estimated. The…

A: Here  given the data we will calculate mean  Population standard deviation is 6 Number of the…

Q: A researcher wants to estimate the mean blood cholesterol level of young men ages 15-25 with a…

A: It is given that the confidence level is 0.8462, the standard deviation is 45, and the margin of…

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 280. Find the 95%…

A: It's a t distribution as the population standard deviation is unknown

Q: Suppose the mean height in inches of all 9th grade students at one high school is estimated. The…

A:

Q: The difference between teenage female and male depression rates estimated from two samples is 0.07.…

A: difference between teenage female and male depression rates estimated from two samples is 0.07 point…

Q: Find a 90% confidence interval for the population mean age of the Smurfs if a sample of 52 smurfs…

A: It is given that, There is a random sample of size 52 and has a mean of 49.7 and the standard…

Q: do the 95% confidence interval for the expected percent change

A: Given data of percentage change over five days as x and percentage change over year as y below…

Q: The mean age from a sample of 45 employees at Stats R Us is 22, with a standard deviation of 4.32.…

A: Sample mean = x̅ = 22 Sample size = n = 45 Sample S.D = s = 4.32 Standard Error = s/√n  =…

Q: The 2018 General Social Survey contains information on the number of poor mental health days adults…

A: Obtain the 95% confidence interval for the mean number of poor mental health days for females.   The…

Q: .2 and X right 2 Find X left for a 95% confidence interval using the chi-square distribution with 9…

A: Given Information: Degrees of freedom df=9 Confidence level =95%=0.95 Significance level…

Q: A mobile phone manufacturer wishes to estimate how frequently their customers buy a new phone. They…

A: Solution: Let X be the random variable. From the given information, x-bar=1.9 years, S=1.2 and n=22.

Q: Selling used cars is often a pain, A lot of selling to do for very little gain My used car lot has…

A: Given, n = 36 mean = 7245 s =  2500 Confidence level = 95%

Q: A popular weight loss program claims users will lose weight each month. Linda samples 25 dieters and…

A: We have given that,  Sample mean (x̄) = 10 pounds, standard deviation (s) = 2 pounds and sample size…

Q: 4. A random sample of 50 individuals are asked of the number of hours spent on social media on a…

A: Suppose that is the population mean number of hours spent on social media per day.

Q: Obesity Obesity is defined as a body mass index (BMI) of 30 kg/m or more. A 99 % confidence interval…

A: From the provided information, Confidence level = 99% Confidence interval = (0.253, 0.271)

Q: Selling used cars is often a pain, A lot of selling to do for very little gain My used car lot has…

A: We have to find given ci.

Q: Find a 99% confidence interval for the population mean age of the Smurfs, if a sample of 50 smurfs…

A:

Q: Eight squirrels were found to have an average weight of 9.7 ounces with a sample standard deviation…

A:

Q: The sample correlation is -0.8. If the sample size was 40, then the 99% confidence interval states…

A:

Q: number

A: Given: Mean, x=3.5 Sample standard deviation, s=1.6 Sample size, n = 219 To compute the confidence…

Q: There is a sample of 30 people and their shower times. What is the 95% confidence interval when…

A: Given Sample size=30 Sample mean=23.50 Standard deviations=9.69

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.