9!+8! 2. 4!3! 10!(12!) 3. 10!-8! 9! %3D %3D 1. %3D 3!3! Р (10,2) 5. P(7,3) Р (20,3). Р(3,4) 6. 20!+3! %3D 4. 9!-3! P(9,8) Р(10,2)-Р(4,2) Р(4,4) Р (8,8). Р(2,2) 8. Р(10,6).Р(4,4) 9.- %3D %3D Р(4,3) P(7,4) 9! %3D 3! II
9!+8! 2. 4!3! 10!(12!) 3. 10!-8! 9! %3D %3D 1. %3D 3!3! Р (10,2) 5. P(7,3) Р (20,3). Р(3,4) 6. 20!+3! %3D 4. 9!-3! P(9,8) Р(10,2)-Р(4,2) Р(4,4) Р (8,8). Р(2,2) 8. Р(10,6).Р(4,4) 9.- %3D %3D Р(4,3) P(7,4) 9! %3D 3! II
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
Answer number 7 to 10 only thanks
Transcribed Image Text:B. Evaluate the following.
9!
1.
3!3!
9!+8!
2.
4!3!
10!(12!)
3.
10!-8!
%3D
%3D
%3D
20!+3!
4.
9!-3!
Р(10,2)
5.
Р(7,3)
Р (20,3). Р(3,4)
6.
%3D
%3D
%3D
Р(9,8)
Р(10,2)-Р(4,2)
7.
P(4,4)
Р (8,8). Р(2,2)
8.
Р(4,3)
Р(10,6).Р(4,4)
9.
%3D
%3D
P(7,4)
9!
10.
3!
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