97. To determine the value of the definite integral: 3 x - 3 x² - 6x + 10 a. Complete the square of the denominator of the integrand: x² - 6x + 10 = (___ _ _)² + __ b. Determine the anti-derivative using an appropriate substitution: x - 3 √₁² x² - 6x + 10 3 dx = c. Use the anti-derivative to evaluate the definite integral: C dx x - 3 2 x² - 6x+10 -dx =
97. To determine the value of the definite integral: 3 x - 3 x² - 6x + 10 a. Complete the square of the denominator of the integrand: x² - 6x + 10 = (___ _ _)² + __ b. Determine the anti-derivative using an appropriate substitution: x - 3 √₁² x² - 6x + 10 3 dx = c. Use the anti-derivative to evaluate the definite integral: C dx x - 3 2 x² - 6x+10 -dx =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![97. To determine the value of the definite integral:
3
1x²-6x +
-dx
- 6x + 10
a. Complete the square of the denominator of the integrand:
x² - 6x + 10 = = (-____-
b. Determine the anti-derivative using an appropriate substitution:
x - 3
√x² - 6x + 10 dx =
-
-
c. Use the anti-derivative to evaluate the definite integral:
3
x - 3
x² - 6x+10
dx =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3eb03a80-7cae-4d33-b228-e2e0361c370e%2F31737511-b2ef-49e4-952d-fd9072198c12%2Ftsm3lsi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:97. To determine the value of the definite integral:
3
1x²-6x +
-dx
- 6x + 10
a. Complete the square of the denominator of the integrand:
x² - 6x + 10 = = (-____-
b. Determine the anti-derivative using an appropriate substitution:
x - 3
√x² - 6x + 10 dx =
-
-
c. Use the anti-derivative to evaluate the definite integral:
3
x - 3
x² - 6x+10
dx =
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