94. Express y as a function of x. The constant C is a positive number. 1n (y + 4) = 5x + In C

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter5: Exponential And Logarithmic Functions
Section5.3: Logarithmic Functions And Their Graphs
Problem 140E
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### Problem:

**Question 94:** 
Express \( y \) as a function of \( x \). The constant \( C \) is a positive number.

\[ \ln(y + 4) = 5x + \ln C \]

### Explanation:

In this problem, we are given a logarithmic equation and need to express \( y \) as a function of \( x \).

### Solution:

1. **Given Equation:**
\[ \ln(y + 4) = 5x + \ln C \]

2. **Use Properties of Logarithms:**
   Isolate the logarithmic expression on one side.

\[ \ln(y + 4) = \ln(Ce^{5x}) \]

   This step uses the property of logarithms: \( \ln(a) + \ln(b) = \ln(ab) \).

3. **Exponentiate both sides to remove the natural log:**

\[ y + 4 = Ce^{5x} \]

4. **Solve for \( y \):**

\[ y = Ce^{5x} - 4 \]

### Result:

The function \( y \) in terms of \( x \) is:

\[ y = Ce^{5x} - 4 \]

Where \( C \) is a positive constant.

This completes the transcription and explanation for expressing \( y \) as a function of \( x \).
Transcribed Image Text:### Problem: **Question 94:** Express \( y \) as a function of \( x \). The constant \( C \) is a positive number. \[ \ln(y + 4) = 5x + \ln C \] ### Explanation: In this problem, we are given a logarithmic equation and need to express \( y \) as a function of \( x \). ### Solution: 1. **Given Equation:** \[ \ln(y + 4) = 5x + \ln C \] 2. **Use Properties of Logarithms:** Isolate the logarithmic expression on one side. \[ \ln(y + 4) = \ln(Ce^{5x}) \] This step uses the property of logarithms: \( \ln(a) + \ln(b) = \ln(ab) \). 3. **Exponentiate both sides to remove the natural log:** \[ y + 4 = Ce^{5x} \] 4. **Solve for \( y \):** \[ y = Ce^{5x} - 4 \] ### Result: The function \( y \) in terms of \( x \) is: \[ y = Ce^{5x} - 4 \] Where \( C \) is a positive constant. This completes the transcription and explanation for expressing \( y \) as a function of \( x \).
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