91. Depth of a Well One method for determining the depth of a well is to drop a stone into it and then measure the time it takes until the splash is heard. If d is the depth of the well (in feet) and t, the time (in seconds) it takes for the stone to fall, then d = 16t, so t = Vd!4. Now if t2 is the time it takes for the sound to travel back up, then d = 1090t2 because the speed of sound is 1090 ft/s. So t2 = d/1090. Thus the total time elapsed between dropping the stone and hearing the splash is Va d 4 1090 How deep is the well if this total time is 3 s? (See the follow- ing figure.) Time Time sound rises: stone falls: va 4 1090
91. Depth of a Well One method for determining the depth of a well is to drop a stone into it and then measure the time it takes until the splash is heard. If d is the depth of the well (in feet) and t, the time (in seconds) it takes for the stone to fall, then d = 16t, so t = Vd!4. Now if t2 is the time it takes for the sound to travel back up, then d = 1090t2 because the speed of sound is 1090 ft/s. So t2 = d/1090. Thus the total time elapsed between dropping the stone and hearing the splash is Va d 4 1090 How deep is the well if this total time is 3 s? (See the follow- ing figure.) Time Time sound rises: stone falls: va 4 1090
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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