4....2 Suppose that P=101lbs. What will the force Q be in this case? -900N-ByP=150N206030180> cx=0ЄFx =0=CxP=150NвDimensions in millimetersPQEFx =0=BxEM c = 0 = By (30mm) + 150N (180mm)By = -900NGEMA=0 = Q(20mm) + (-900 N) (60 mm)Q= 2700 N

Answered: -900N-By P=150N 20 60 30 180 > cx=0 ЄFx…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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-900N-By P=150N 20 60 30 180 > cx=0 ЄFx =0=Cx P=150N в Dimensions in millimeters P Q EFx =0=Bx EM c = 0 = By (30mm) + 150N (180mm) By = -900N GEMA=0 = Q(20mm) + (-900 N) (60 mm) Q = 2700 N