Answered: 900 students were surveyed and had an…

900 students were surveyed and had an average GPA of 2.7 with a standard deviation of 0.4. Calculate the margin of error for a 95% confidence level:

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Q: A sample of 22 public high school students spent an average of 6.5 hours studying per week. Assume…

Q: A boxer would like to know the mean diameter of a navel orange. If the standard deviation is 0.3…

A: Given Standard deviations=0.3 Margin of error=0.1 At 95% confidence z=1.96

Q: the standard deviation of the 16 observations was 0.95 inches (again, the sample mean was 17.2).…

A: Given : Standard deviation of the 16 observations was 0.95 inches & the sample mean was 17.2.…

Q: In a random sample of ten people, the mean driving distance to work was 19.2 miles and the…

Q: A community hospital wants to estimate the body mass index (BMI) of its local population. To…

Q: he average weight of 20 randomly selected cars was 3500 pounds. The sample standard deviation was…

A: given data, n=20df=n-1=20-1=19x¯=3500 pounds s=315 pounds CI=0.90α=1-0.90=0.10

Q: In a random sample of seven people, the mean driving distance to work was 19.7 miles and the st and…

A: From provided information, random sample of 7 people is considered. The mean distance to work was…

Q: Find the value of za/2 that corresponds to a confidence level of 89.48%.

A: Confidence level: C=0.8948

Q: Find the margin of error for the following; 95% confidence, sample mean is 32.5, standard deviation…

Q: Michelle takes a sample of 25 different-gender married couples. In her sample, she found that the…

Q: You measure 24 textbooks' weights, and find they have a mean weight of 53 ounces. Assume the…

A: Given that, x¯=53,n=24,σ=12.9 Critical value: By using the z-tables, the critical value at 5% level…

Q: A survey of college students reported that in a sample of 371 male students, the average number of…

A: Obtain the 98% confidence interval for the difference between men and women in the mean number of…

Q: 300 high school students were asked how many hours of TV they watch per day. The mean was 2 hours,…

Q: A runner wants to know her average mile running time. She records a sample of 25 running times. The…

A: Solution: Let X be the mile running time. From the given information, x-bar=6.5 minutes, s=0.7…

Q: given a standard deviation of + or - 0.023m at the 90% confidence level, what is the 68% error level…

A: The confidence level of the data is 90%. The standard deviation of the data with error percentage is…

Q: The mean time taken to design a house plan by 40 architects was found to be 19 hours with a standard…

A: Step 1:Given data :Sample size n=40degrees of freedom df=40−1=39Sample mean xˉ=19Sample standard…

Q: In a random sample of eight cell phones, the mean full retail price was $468.50 and the standard…

A: The information provided in the question are as follows :- Sample size (n) = 8 Sample mean (x̄) =…

Q: A sample of 22 public high school students spent an average of 6.5 hours studying per week. Assuming…

A: Given: Sample Sizen=22Sample MeanX=6.5Standard Deviationσ=2.3 The z value corresponding to…

Q: In a random sample of five people, the mean driving distance to work was 22.5 miles and the standard…

Q: In a random sample of twelve cell phones, the mean full retail price was $566.50 and the standard…

Q: use the t-distribution to find the margin of error and construct a 90% confidence interval for the…

A: Given that Sample size (n) = 12 Mean full retail price (x¯)= $597 Standard deviation (s) = $168…

Q: A sample of 22 public high school students spent an average of 6.5 hours studying per week. Assuming…

Q: The prices of used books at a large college bookstore are normally distributed. If a sample of 23…

Q: Calculate the lower endpoint of a two-sided 95% confidence interval for the population mean using…

A: given data sample size (n) = 41sample mean ( x¯ ) = 11.92population standard deviation (σ) = 1.8195%…

Q: for a sample of 150 that has a mean of 6540 and a standard deviation of .89, calculate the 95%…

A: It is given that mean and standard deviation are 6,540 and 0.89, respectively.

Q: You measure 46 textbooks' weights, and find they have a mean weight of 34 ounces. Assume the…

A: given data population sd(σ) = 14.3n = 46x¯ = 3495% ci for mean (μ) = ?

Q: Kennedy High School reported that the mean score on an end of semester physics exam wass 508 with a…

A: Given, Mean score μ=508Standard deviation σ=121Sample size n=200

Q: In a sample of 32 students, the mean scholarship amount received was $887, with a standard deviation…

A: Given information: n=32x¯=887s=27.4 df=n-1=32-1=31 Confidence level is 90% Significance level is…

Q: ten cell phones, the mean full retail price was $406.50 and the standard deviation was $174.00.…

A: Given that Sample size n =10 Sample mean =406.50 Sample standard deviation =174.00

Q: In a random sample of six people, the mean driving distance to work was 24.3 miles and the…

Q: n a random sample of six mobile devices, the mean repair cost was $65.00 and the standard deviation…

Q: an education support group wants to estimate the mean class size for elementary schools in the…

A: Given that confidence level is, C=99%=99/100=0.99 The level of significance is, α=1-C=1-0.99=0.01…

Q: 300 high school students were asked how many hours of TV they watch per day. The mean was 2 hours,…

A: It is given that the confidence level is 0.90.

Q: a. b. Find the best point estimate of the population mean. Construct and interpret the 85%…

A: here given , sample size = n= 20 sample mean = $48.60 sample standard deviation = $3.53 here…

Q: In a random sample of seven cell phones, the mean full retail price was $402.50 and the standard…

Q: In a random sample of eight cell phones, the mean full retail price was $431.50 and the standard…

Q: 300 high school students were asked how many hours.of TV they watch per day. The mean was 2 hours,…

A: Given that: Mean=2 Standard deviation=SD=σ= 0.5 Confidence level= 90% n=sample size=n=300 So…

Q: A local bank needs information concerning the checking account balances of its customers. A random…

Question

100%

900 students were surveyed and had an average GPA of 2.7 with a standard deviation of 0.4. Calculate the margin of error for a 95% confidence level:

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

You measure 25 randomly selected textbooks' weights, and find they have a mean weight of 73 ounces. Assume the population standard deviation is 5.8 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight.
A group of 49 randomly selected students has a mean age of 22.4 years. Assume the population standard deviation is 3.8. Construct a 90% confidence interval for the population mean. Include a statement interpreting your answer.
The standard deviation, S, for the annual medical cost of 24 households was found to equal $1689 find a 95% confidence interval for the standard deviation of the annual medical cost for all households. Assume medical costs are normally distributed.
You measure 33 textbooks' weights, and find they have a mean weight of 62 ounces. Assume the population standard deviation is 4.6 ounces. Based on this, construct a 95% confidence interval for the true population mean textbook weight
In a recent sample of 89 used cars sales costs, the sample mean was $6,225 with a standard deviation of $3,151. Assume the underlying distribution is approximately normal. Which distribution should you use for this problem? Construct a 95% confidence interval for the population mean cost of a used car.
In a random sample of 5 mobile devices, the mean repair cost was $60.00 and the standard deviation was $12.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval for the population mean. Interpret the results.
In a random sample of 17 people, the mean commute time to work was 30.2 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t- distribution to construct a 95% confidence interval for the population mean y. What is the margin of error of y? Interpret the results.
A survey of 73 randomly selected homeowners finds that they spend a mean of $74 per month on home maintenance. Construct a 95% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners. Assume that the population standard deviation is $16 per month. Round to the nearest cent.
You are trying to determine that average height of females living in New Jersey. To estimate this population mean, you collect a sample of 100 women and the average height of the women sampled was 54.5 inches. Assume the standard deviation of the population is 3 inches. Using a 95% confidence level, determine the following: a. Based on the poll, what is the point estimate of the mean height of female NJ residents? b. Find the margin of error for this sample. c. Construct a confidence interval to estimate the mean height of female NJ residents using a 95% confidence level. d. What sample size would be required to achieve a margin of error of less than 1 inch ?