Please solve this detailed step by step 9.9A 2 m wide square foundation is placed at a depth of 1.5 m,in a very thick homogeneous sand deposit where q₁ =10 MN/m² and y=18.5 kN/m³. The stress level at the foun-dation is 140 kN/m². Estimate the settlement in 25 years,using the method of Schmertmann et al. [Eq. (9.30)]. Howmuch of this settlement is due to creep?

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Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter9: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 9.9P

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A 2 m wide square foundation is placed at a depth of 1.5 m, in a very thick homogeneous sand deposit where q. 10 MN/m? and y = 18.5 kN/m³. The stress level at the foun- dation is 140 kN/m². Estimate the settlement in 25 years, using the method of Schmertmann et al. [Eq. (9.30)]. How much of this settlement is due to creep? 9.9
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subject: Geotechnical Engineeringbook: principle of foundation engineering - Braja M Das
Estimate the ultimate consolidation settlement under the centerline of a 25 x 25 meter mat foundation. The mat is 1.5 meter thick reinforced concrete (ϒconcrete = 23.6 kN / m3), and the average stress on the surface of the slab is 125 kPa. The soil profile is shown in the figure below. Lab testing on samples of the clay showed that the clay is normally consolidated and that Cc = 0.40, Cr = 0.03, and eo = 1.13. Neglect any settlements due to the sand layer. Divide the clay layer into four thinner layers of thickness 2.0, 2.0, 3.0, and 3.0 meters.
8.4 A rectangular foundation is shown in Figure P8.2, given B=2m, L=4m q = 240 kN/m², H = 6m, and D; = 2 m. (a) Assuming E = 3800KN/m², calculate the average elastic settlement. Use Eq. (8.24). (b) If the clay is normally consolidated, calculate the consolidation settlement. Use Eq. (8.35) and y,t = 17.5 kN/m’, C, = 0.12, and e, = 1.1. %3D G.W.T. D,=2 m = 240 kN/m² Clay e. = .IO H= 6 m 1. Rock Figure P8.2 S,(average) = µ,M0 qB (v = 0.5) E (8.24) (8.35)
Following are the results of a standard penetration test in the field (sandy soil): Depth (m) Field value of N60 1.5 3.0 12 4.5 11 6.0 7.5 13 9.0 11 10.5 13 Estimate the net allowable bearing capacity of a mat foundation 6.5 m x 5.0 m in plan. Here, Df = 1.5 m , and allowable settlement 50 mm. Assume that the unit weight of soil (v) = 16.5 KN/m³ Select one: O a. 30.23 kN/m2 O b. 365.86 kN/m² c. 302.3 kN/m2 O d. 302.3 N/m
8.4 A rectangular foundation is shown in Figure P8.2, given B= 2 m, L=4m q=240 kN/m², H=6m, and D; =2 m. (a) Assuming E = 3800KN/m², calculate the average elastic settlement. Use Eq. (8.24). (b) If the clay is normally consolidated, calculate the consolidation settlement. Use Eq. (8.35) and yat = 17.5 kN/m², C¸ = 0.12, and e, = 1.1.
Repeat Problem 8.2 for an allowable settlement of 25 mm.
Estimate the increase in vertical stress at 0.5 m depth intervals, within the clay layer, below point A (See figure below). The foundation exerts a uniform vertical stress of 120 kPa at ground level. Using these values estimate the settlement due to the clay layer. (Hand in any graphs used) 5m 5m 2m 3m Very Dense Sand 2m 1.5m Clay E=3.5 MPa 2m Bedrock Soil profile A Plan of building 3m Soil profile and plan for Question 4 3m FA
(b) Figure Q2 (b) shows the ring foundation to support a silo. Given R1 = 3 m while R2 =6 m. The total vertical load is 7500 kN. (i) Calculate and plot the vertical stress increase with depth up to 7 m (use 1 minterval) under the centre of the ring (point O).(ii) Determine the maximum vertical stress increase and its location.
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