9.30 A hot solution of Ba(NO3)2 from an evaporator contains 30.6 kg of Ba(NO3)2 per 100 kg of water and goes to a crystallizer where the solution is.cooled and Ba(NO,), crystallizes. On cooling 10% of the original water present evaporates. For a feed solu- tion of 100 kg, calculate the following: (a) The yield of crystals if the solution is cooled to 290 K, if the solubility is 8.6 kg Ba(NO3)-/100 kg total water at 290 K (b) The yield if cooled to 283 K, if the solubility is 7.0 kg Ba(NO3)½/100 kg total HOL To 10 water at 283 K
9.30 A hot solution of Ba(NO3)2 from an evaporator contains 30.6 kg of Ba(NO3)2 per 100 kg of water and goes to a crystallizer where the solution is.cooled and Ba(NO,), crystallizes. On cooling 10% of the original water present evaporates. For a feed solu- tion of 100 kg, calculate the following: (a) The yield of crystals if the solution is cooled to 290 K, if the solubility is 8.6 kg Ba(NO3)-/100 kg total water at 290 K (b) The yield if cooled to 283 K, if the solubility is 7.0 kg Ba(NO3)½/100 kg total HOL To 10 water at 283 K
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:9.6
100 kg water
9.30 A hot solution of Ba(NO3)2 from an evaporator contains 30.6 kg of Ba(NO3)2 per 100
kg of water and goes to a crystallizer where the solution is.cooled and Ba(NO)2
crystallizes. On cooling 10% of the original water present evaporates. For a feed solu-
tion of 100 kg, calculate the following:
(a) The yield of crystals if the solution is cooled to 290 K, if the solubility is 8.6 kg
Ba(NO3)2/100 kg total water at 290 K
(b) The yield if cooled to 283 K, if the solubility is 7.0 kg Ba(NO3),/100 kg total
O-HOL
water at 283 K
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