9.14 Perform the same computation as in Example 9.11, but use five parachutists with the following characteristics: Parachutist Mass, kg Drag Coefficient, kg/s 55 75 60 75 90 10 12 15 16 10 The parachutists have a velocity of 9 m/s. -2345
9.14 Perform the same computation as in Example 9.11, but use five parachutists with the following characteristics: Parachutist Mass, kg Drag Coefficient, kg/s 55 75 60 75 90 10 12 15 16 10 The parachutists have a velocity of 9 m/s. -2345
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
The question is in the picture
![9.14 Perform the same computation as in Example 9.11, but use
five parachutists with the following characteristics:
Parachutist
Mass, kg
Drag Coefficient, kg/s
55
75
60
75
90
10
12
15
16
10
The parachutists have a velocity of 9 m/s.
-2345](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf88238a-88fe-4510-8f0f-e30421837b9a%2Fccce9e47-dc6f-49b1-93d1-b8a57cf4de06%2Ftn9hwv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9.14 Perform the same computation as in Example 9.11, but use
five parachutists with the following characteristics:
Parachutist
Mass, kg
Drag Coefficient, kg/s
55
75
60
75
90
10
12
15
16
10
The parachutists have a velocity of 9 m/s.
-2345
![EXAMPLE 9.11
Solution of Linear Algebraic Equations Using the Computer
Problem Statement. A computer program to solve linear algebraic equations such
as one based on Fig. 9.6 can be used to solve a problem associated with the falling
parachutist example discussed in Chap. 1. Suppose that a team of three parachutists
is connected by a weightless cord while free-falling at a velocity of 5 m/s (Fig. 9.7).
270
GAUSS ELIMINATION
3
1
FIGURE 9.8
Free-body diagrams for each of the three falling parachutists.
Calculate the tension in each section of cord and the acceleration of the team, given
the following:
Parachutist
Mass, kg
Drag Coefficient, kg/s
70
10
60
14
40
Solution. Free-body diagrams for each of the parachutists are depicted in Fig. 9.8.
Summing the forces in the vertical direction and using Newton's second law gives a set
of three simultaneous linear equations:
= mja
m2g + T- czv - R = mza
- Czv + R = mya
mig - T - Cu
These equations have three unknowns: a, T, and R. After substituting the known values,
the equations can be expressed in matrix form as (g = 9.81 m/s),
FIGURE 9.7
(636.7
= {518.6
307.4
70
Three parachutists freefalling
while connected by weightless
cords.
60
-1
40
This system can be solved using your own software. The result is a = 8.6041 m/s;
T = 34.4118 N; and R- 36.7647 N.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf88238a-88fe-4510-8f0f-e30421837b9a%2Fccce9e47-dc6f-49b1-93d1-b8a57cf4de06%2F1cpsx08_processed.jpeg&w=3840&q=75)
Transcribed Image Text:EXAMPLE 9.11
Solution of Linear Algebraic Equations Using the Computer
Problem Statement. A computer program to solve linear algebraic equations such
as one based on Fig. 9.6 can be used to solve a problem associated with the falling
parachutist example discussed in Chap. 1. Suppose that a team of three parachutists
is connected by a weightless cord while free-falling at a velocity of 5 m/s (Fig. 9.7).
270
GAUSS ELIMINATION
3
1
FIGURE 9.8
Free-body diagrams for each of the three falling parachutists.
Calculate the tension in each section of cord and the acceleration of the team, given
the following:
Parachutist
Mass, kg
Drag Coefficient, kg/s
70
10
60
14
40
Solution. Free-body diagrams for each of the parachutists are depicted in Fig. 9.8.
Summing the forces in the vertical direction and using Newton's second law gives a set
of three simultaneous linear equations:
= mja
m2g + T- czv - R = mza
- Czv + R = mya
mig - T - Cu
These equations have three unknowns: a, T, and R. After substituting the known values,
the equations can be expressed in matrix form as (g = 9.81 m/s),
FIGURE 9.7
(636.7
= {518.6
307.4
70
Three parachutists freefalling
while connected by weightless
cords.
60
-1
40
This system can be solved using your own software. The result is a = 8.6041 m/s;
T = 34.4118 N; and R- 36.7647 N.
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