9.13 Chapter 9: Section Exercises (Example 30) Income in Maryland According to a 2018 Money magazine article, Maryland has one of the highest per capita incomes in the United States, with an average income of $75,847. Suppose the standard deviation is $32,000 and the distribution is right-skewed. A random sample of 100 Maryland residents is taken. a. Is the sample size large enough to use the Central Limit Theorem for means? Explain. b. What would the mean and standard error for the sampling distribution? c. What is the probability that the sample mean will be more than $3200 away from the population mean?
9.13 Chapter 9: Section Exercises (Example 30) Income in Maryland According to a 2018 Money magazine article, Maryland has one of the highest per capita incomes in the United States, with an average income of $75,847. Suppose the standard deviation is $32,000 and the distribution is right-skewed. A random sample of 100 Maryland residents is taken. a. Is the sample size large enough to use the Central Limit Theorem for means? Explain. b. What would the mean and standard error for the sampling distribution? c. What is the probability that the sample mean will be more than $3200 away from the population mean?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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9.13
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9.1
S
Section
Paired...
9.13
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Chapter 9: Section Exercises
(Example 3) Income in Maryland According to a 2018 Money magazine article,
Maryland has one of the highest per capita incomes in the United States, with an
average income of $75,847. Suppose the standard deviation is $32,000 and the
distribution is right-skewed. A random sample of 100 Maryland residents is taken.
a. Is the sample size large enough to use the Central Limit Theorem for means?
Explain.
b. What would the mean and standard error for the sampling distribution?
c. What is the probability that the sample mean will be more than $3200 away
from the population mean?
Income in Kansas According to a 2018 Money magazine article, the average income in
Kansas is $53,906. Suppose the standard deviation is $3000 and the distribution of
income is right-skewed. Repeated random samples of 400 Kansas residents are taken,
and the sample mean of incomes is calculated for each sample.
a. The population distribution is right-skewed. Will the distribution of sample
means be Normal? Why or why not?
b. Find and interpret a z-score that corresponds with a sample mean of $53,606.
489
AP -](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1e55cce6-8dd8-4d96-a1ef-b3dd789d2a84%2Fae883544-b2d9-42ff-b85d-c831092f256e%2Fpfrnyu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:X
Clear
9.1
S
Section
Paired...
9.13
9.14
20108021ocation-787 B 10 %3A ...
E
Chapter 9: Section Exercises
(Example 3) Income in Maryland According to a 2018 Money magazine article,
Maryland has one of the highest per capita incomes in the United States, with an
average income of $75,847. Suppose the standard deviation is $32,000 and the
distribution is right-skewed. A random sample of 100 Maryland residents is taken.
a. Is the sample size large enough to use the Central Limit Theorem for means?
Explain.
b. What would the mean and standard error for the sampling distribution?
c. What is the probability that the sample mean will be more than $3200 away
from the population mean?
Income in Kansas According to a 2018 Money magazine article, the average income in
Kansas is $53,906. Suppose the standard deviation is $3000 and the distribution of
income is right-skewed. Repeated random samples of 400 Kansas residents are taken,
and the sample mean of incomes is calculated for each sample.
a. The population distribution is right-skewed. Will the distribution of sample
means be Normal? Why or why not?
b. Find and interpret a z-score that corresponds with a sample mean of $53,606.
489
AP -
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