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9.11 (a) Sometimes the programmable MUX (1) in Figure 9-35 helps us to save AND gates. Consider the case in which F = c'd' + bc' + a'c. If programmable MUX (1) is not set to invert F (i.e., G = F), how many AND gates are needed? If the MUX is set to invert F (i.e., G = F'), how many AND gates are needed? (b) Repeat (a) for F = a'b' + c'd'.

9.11 (a) Sometimes the programmable MUX (1) in Figure 9-35 helps us to save AND gates. Consider the case in which F = c'd' + bc' + a'c. If programmable MUX (1) is not set to invert F (i.e., G = F), how many AND gates are needed? If the MUX is set to invert F (i.e., G = F'), how many AND gates are needed? (b) Repeat (a) for F = a'b' + c'd'.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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9.11 (a) Sometimes the programmable MUX (1) in Figure 9-35 helps us to save AND gates. Consider the case in which F = c'd' + bc' + a'c. If programmable MUX (1) is not set to invert F (i.e., G = F), how many AND gates are needed? If the MUX is set to invert F (i.e., G = F'), how many AND gates are needed? (b) Repeat (a) for F= a'b' + c'd'.
Transcribed Image Text:9.11 (a) Sometimes the programmable MUX (1) in Figure 9-35 helps us to save AND gates. Consider the case in which F = c'd' + bc' + a'c. If programmable MUX (1) is not set to invert F (i.e., G = F), how many AND gates are needed? If the MUX is set to invert F (i.e., G = F'), how many AND gates are needed? (b) Repeat (a) for F= a'b' + c'd'.
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