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9.1. Exercise 1 Consider the generic interface Pair: public interface Pairck, V> { public K getkey(); public V getValue(); Write a class SuccessivePair implementing the Pair interface. The class has two instance variables which are predecessor (of type K) and successor (of type V). Define the constructor of the class SuccessivePair that initializes the instance variables. 9.2. Exercise 2 In a class named Util, define a generic method, areSuccssive, which takes two objects of the same type implementing Comparable interface. Based on compareto method, areSuccssive returns true if the first precede the second with exactly 1 (value returned by compareTo is -1), otherwise, it returns false. Test your areSuccssive method. Examples: SuccessivePaircstring, String> pl = new SuccessivePairc> ("Apple", "Banana"); SuccessivePaircstring, String> p4 = new SuccessivePairco("Orange", "Kiwi"); Util.areSuccessive(p1.getkey(), p1.getValue()); // will return true Util.areSuccessive(p4.getkey(), p4.getValue()); // will return false

9.1. Exercise 1 Consider the generic interface Pair: public interface Pairck, V> { public K getkey(); public V getValue(); Write a class SuccessivePair implementing the Pair interface. The class has two instance variables which are predecessor (of type K) and successor (of type V). Define the constructor of the class SuccessivePair that initializes the instance variables. 9.2. Exercise 2 In a class named Util, define a generic method, areSuccssive, which takes two objects of the same type implementing Comparable interface. Based on compareto method, areSuccssive returns true if the first precede the second with exactly 1 (value returned by compareTo is -1), otherwise, it returns false. Test your areSuccssive method. Examples: SuccessivePaircstring, String> pl = new SuccessivePairc> ("Apple", "Banana"); SuccessivePaircstring, String> p4 = new SuccessivePairco("Orange", "Kiwi"); Util.areSuccessive(p1.getkey(), p1.getValue()); // will return true Util.areSuccessive(p4.getkey(), p4.getValue()); // will return false

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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9.3. Exercise 3 In the class named Util, overload the generic method, areSuccssive, which takes two objects of type SuccessivePair<T, T>, where T implements Comparable<T> interface. Two objects of type SuccessivePair<T, T> are considered successive if the value of the first precede the key of the second (use areSuccssive from the Exercise 2). Test your new areSuccssive method. Examples: SuccessivePair<String, String> pl = new SuccessivePairc>("Apple", "Banana"); SuccessivePair<String, String> p2 = new SuccessivePair<>("Cherry", "Dates"); SuccessivePaircstring, String> p3=new SuccessivePairc>("Elderberry", "Fig"); Util.areSuccessive(p1, p2); // will return true Util.areSuccessive(p2, p3); // will return true Util.areSuccessive(p1, p3); // will return false
Transcribed Image Text:9.3. Exercise 3 In the class named Util, overload the generic method, areSuccssive, which takes two objects of type SuccessivePair<T, T>, where T implements Comparable<T> interface. Two objects of type SuccessivePair<T, T> are considered successive if the value of the first precede the key of the second (use areSuccssive from the Exercise 2). Test your new areSuccssive method. Examples: SuccessivePair<String, String> pl = new SuccessivePairc>("Apple", "Banana"); SuccessivePair<String, String> p2 = new SuccessivePair<>("Cherry", "Dates"); SuccessivePaircstring, String> p3=new SuccessivePairc>("Elderberry", "Fig"); Util.areSuccessive(p1, p2); // will return true Util.areSuccessive(p2, p3); // will return true Util.areSuccessive(p1, p3); // will return false
9.1. Exercise 1 Consider the generic interface Pair: public interface Pairck, V> { public K getkey(); public V getvalue(); } Write a class SuccessivePair implementing the Pair interface. The class has two instance variables which are predecessor (of type K) and successor (of type V). Define the constructor of the class SuccessivePair that initializes the instance variables. 9.2. Exercise 2 In a class named Util, define a generic method, areSuccssive, which takes two objects of the same type implementing ComparableT> interface. Based on compareto method, areSuccssive returns true if the first precede the second with exactly 1 (value returned by compareTo is -1), otherwise, it returns false. Test your areSuccssive method. Examples: SuccessivePair<String, String> pl = new SuccessivePair<>("Apple", "Banana"); SuccessivePair<String, String> p4 = new SuccessivePair<>("Orange", "Kiwi"); Util.areSuccessive(p1.getkey(), p1.getValue()); // will return true Util.areSuccessive(p4.getkey(), p4.getValue()); // will return false
Transcribed Image Text:9.1. Exercise 1 Consider the generic interface Pair: public interface Pairck, V> { public K getkey(); public V getvalue(); } Write a class SuccessivePair implementing the Pair interface. The class has two instance variables which are predecessor (of type K) and successor (of type V). Define the constructor of the class SuccessivePair that initializes the instance variables. 9.2. Exercise 2 In a class named Util, define a generic method, areSuccssive, which takes two objects of the same type implementing ComparableT> interface. Based on compareto method, areSuccssive returns true if the first precede the second with exactly 1 (value returned by compareTo is -1), otherwise, it returns false. Test your areSuccssive method. Examples: SuccessivePair<String, String> pl = new SuccessivePair<>("Apple", "Banana"); SuccessivePair<String, String> p4 = new SuccessivePair<>("Orange", "Kiwi"); Util.areSuccessive(p1.getkey(), p1.getValue()); // will return true Util.areSuccessive(p4.getkey(), p4.getValue()); // will return false
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