9.1 For an NMOS differential pair with a common-mode voltage VCM applied, as shown in Fig. 9.2, let VDD=Vss = 1.0 V, k = 0.4 mA/V², (W/L)₁2 = 10, V₁ = 0.4 V, I = 0.16 mA, R₁ = 5 ks, and neglect channel-length modulation. (a) Find Voy and Vas for each transistor. GS (b) For VCM = 0, find VS, ID, ID2, VD₁, and VD2. (c) Repeat (b) for VCM = +0.4 V. (d) Repeat (b) for VCM = -0.1 V. (e) What is the highest value of VCM for which Q, and Q₂ remain in saturation? (f) If current source I requires a minimum voltage of 0.2 V to operate properly, what is the lowest value allowed for V. and hence for V...?

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9.1 For an NMOS differential pair with a common-mode
voltage VCM applied, as shown in Fig. 9.2, let VDD = VSS = 1.0 V,
|k, = 0.4 mA/V², (W/L)₁,2 = 10, V₁ = 0.4 V, I = 0.16 mA,
R₂ = 5 ks, and neglect channel-length modulation.
(a) Find Voy and VGs for each transistor.
(b) For VCM = 0, find VS, ID1, D2, VD1, and VD2-
(c) Repeat (b) for VCM = +0.4 V.
(d) Repeat (b) for VCM = -0.1 V.
(e) What is the highest value of VCM for which Q₁ and Q₂
remain in saturation?
(f) If current source I requires a minimum voltage of 0.2 V
to operate properly, what is the lowest value allowed for
V, and hence for VCM?
Rp
UD₁ = VDD - 1 R₁0√1/2 1/2 √
Q₂
VCM (+
VDD
VGS
2₁
√1/2 1/2
-Vs
SS
RD
VGS
Vs = VCM - VGS
I
-OUD2 = VDD / RD
VGS = V₁ + Vov
+VCM
= V₁ + √(1/(KW)
Figure 9.2 The MOS differential pair with a common-mode input voltage VCM
Transcribed Image Text:9.1 For an NMOS differential pair with a common-mode voltage VCM applied, as shown in Fig. 9.2, let VDD = VSS = 1.0 V, |k, = 0.4 mA/V², (W/L)₁,2 = 10, V₁ = 0.4 V, I = 0.16 mA, R₂ = 5 ks, and neglect channel-length modulation. (a) Find Voy and VGs for each transistor. (b) For VCM = 0, find VS, ID1, D2, VD1, and VD2- (c) Repeat (b) for VCM = +0.4 V. (d) Repeat (b) for VCM = -0.1 V. (e) What is the highest value of VCM for which Q₁ and Q₂ remain in saturation? (f) If current source I requires a minimum voltage of 0.2 V to operate properly, what is the lowest value allowed for V, and hence for VCM? Rp UD₁ = VDD - 1 R₁0√1/2 1/2 √ Q₂ VCM (+ VDD VGS 2₁ √1/2 1/2 -Vs SS RD VGS Vs = VCM - VGS I -OUD2 = VDD / RD VGS = V₁ + Vov +VCM = V₁ + √(1/(KW) Figure 9.2 The MOS differential pair with a common-mode input voltage VCM
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