Answered: 9.05 L9.05 L container holds a mixture…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

A 9.05 L9.05 L container holds a mixture of two gases at 41 °C.41 °C. The partial pressures of gas A and gas B, respectively, are 0.380 atm0.380 atm and 0.665 atm.0.665 atm. If 0.230 mol0.230 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?

Expert Solution

Step 1

Volume of container =9.05 L

Temperature (T) = 41°C = 41 + 273 = 314 K

Partial pressure of gas A = 0.380 atm

Partial pressure of gas B = 0.665 atm

Mole of third gas C added = 0.230 mole

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