9. (x+2)² +(y+9)² = 196 Center: Circumference:

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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9.
### Standard Form of a Circle

Consider the equation given:

\[ (x + 2)^2 + (y + 9)^2 = 196 \]

This equation represents a circle in standard form, \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius.

**Exercise 9:**

Given the equation:
\[ (x + 2)^2 + (y + 9)^2 = 196 \]

- **Identify the Center:** 
  The center \((h, k)\) of the circle can be found directly from the equation. In this case, \((h, k)\) is \((-2, -9)\).

- **Calculate the Circumference:** 
  The radius \(r\) is the square root of the right side of the equation.
  \[
  r^2 = 196 \implies r = \sqrt{196} = 14
  \]
  The circumference \(C\) of the circle is given by the formula \(C = 2\pi r\).
  \[
  C = 2\pi \times 14 = 28\pi
  \]

**Form Format to Complete:**

- **Center:** \( (-2, -9) \)
- **Circumference:** \( 28\pi \)

This exercise helps you understand how to extract the center and radius from the standard form of a circle equation and subsequently use the radius to determine the circumference of the circle.
Transcribed Image Text:### Standard Form of a Circle Consider the equation given: \[ (x + 2)^2 + (y + 9)^2 = 196 \] This equation represents a circle in standard form, \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center of the circle and \(r\) is the radius. **Exercise 9:** Given the equation: \[ (x + 2)^2 + (y + 9)^2 = 196 \] - **Identify the Center:** The center \((h, k)\) of the circle can be found directly from the equation. In this case, \((h, k)\) is \((-2, -9)\). - **Calculate the Circumference:** The radius \(r\) is the square root of the right side of the equation. \[ r^2 = 196 \implies r = \sqrt{196} = 14 \] The circumference \(C\) of the circle is given by the formula \(C = 2\pi r\). \[ C = 2\pi \times 14 = 28\pi \] **Form Format to Complete:** - **Center:** \( (-2, -9) \) - **Circumference:** \( 28\pi \) This exercise helps you understand how to extract the center and radius from the standard form of a circle equation and subsequently use the radius to determine the circumference of the circle.
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