9. When birth weights were recorded for a simple random sample of 18 male babies born to mothers in a region taking a special vitamin supplement, the sample had a mean of 3.857 kilograms and a standard deviation of 0.664 kilogram. Use a 0.05 significance level to test the claim that the mean birth weight for all male babies of mothers given vitamins is different from 3.38 kilograms, which is the mean for the population of all males in this particular region. Based on these results, does the vitamin supplement appear to have an effect on birth weight? See examples we did in class in section 10.1 and use t-distribution to find the P-value.

Q: 4s +5 S -4

A:

Q: (3c)²(3c)³

A: To solve 3c23c3

Q: b2 over b-a + a2 over a-b

A:

Q: how does the a in the second row become a 0

A: It is given that the row operations are performed on matrices as, 010-10a0-a0~01a-10a000~-10a010000…

Q: 3. (a - 4)(a + 5) 6. (a+ 1)(a - 11) 9. (a+3)(a + 3)

A:

Q: | 8 - 3s | = 9/2

A: To solve: |8-3s|=92 Solution: |8-3s|=92 On simplifying further we get: |8-3s|=92⇒8-3s=±92…

Q: Find m2C and mZD. B. (3c - 17) (c+ 1) A

A:

Q: Г(4) 2Г (2) 3 aO 2.00 6. 4.

A:

Q: 23-8K

A:

Q: 7(n-2)=28

A: Solving for n

Q: 2(-ャ) n=2

A:

Q: 18) 2x y

A:

Q: 5 3 + s2-8 s2+ 3.

A:

Q: 2(3+3+9-8)-6

A: Given data:- 2(3+3+9-8)-6

Q: -4-3|4-4*2|

A: This is a basic question including a modulus function. in this |4-4*2|=|4-8|=|-4| Modulus function…

Q: 6+5x(8/2)2

A:

Q: OA = (3,4-1) OB = (2,0,1) AB

A:

Q: b. Px(m + n)- 16(m+ n) (x² 主 - 4) (x + ) (m + n)

A:

Q: 4. Find m RS. (5x+ 6) S. (11r- 72) If MD- E 24and DN- 2. A ind MD

A: As per our guideline we are allowed to do 1 question at a time. Please post other questions next…

Q: ind (2× - 7)²

A: Given: 2x-72

Q: ?dz (2²+36)*

A:

Q: -6 (0 Find A-' if A 2 -4 -3 10

A:

Q: 40 (3x +10)°

A: Using concept of opposite Angles.

Q: -2(5a)

A: To evaluate-2(5a)

Q: (n+3)!

A: (n+3)!/n! =(n+3)(n+2)!/n!

Q: 6 4. Find A: s²+4 R: r()

A:

Q: 15. 423-922 + 72 +3)e- dz

A:

Q: 10 = 2(p + -4)

A: Given  10 = 2(p + -4) p =?

Q: Simpliny 3.5 )(ab)s (Vą Vbc) va

A:

Q: 2х (b) 2 +1)

A:

Q: 10. 3 + Зу- 1 + у

A: Given that                     3+3y-1+y Now we simplify this.                           3+3y-1+y…

Q: 2(3w+8)=40

A:

Q: -5,4y+14-2y=4

A: Given ,  4y + 14 - 2y = 4     ....... (1)  We have to find value of y  (1) implies

Q: 3 27 ||

A: The given expression is 8273

Q: x3 f) x2+2x+1

A:

Q: (3a − 8)2

A: Given query is to simplify the expression.

Q: -5+2(8-12)

A: Use PEMDAS rule to simplify.First we work with the parenthesis. In it 8-12=-4

Q: Find f- (3) – 4ƒ(6).

A: Given: The table x f(x) 1 4 2 1 3 2 4 6 5 3 6 5