9. Water gas is a 1:1 mole ratio of CO (g) and H, (g). It is burned in air: 2CO(g) + O,(g) 2CO,(g) A,H =-566 kJ mol > %3D 2H,(g) + O2(g) - → 2H,0(1) A,H =-571.7 kJ mol (1) Find the number of moles of CO (g) and H, (g) present in 50.0 g of water gas. (Remember that they are present in a 1: 1 mole ratio). (2) Use the preceding thermochemical equations to find the enthalpy change when 50.0 g of water gas are burned in air.

9. Water gas is a 1:1 mole ratio of CO (g) and H, (g). It is burned in air: 2CO(g) + O,(g) 2CO,(g) A,H =-566 kJ mol > %3D 2H,(g) + O2(g) - → 2H,0(1) A,H =-571.7 kJ mol (1) Find the number of moles of CO (g) and H, (g) present in 50.0 g of water gas. (Remember that they are present in a 1: 1 mole ratio). (2) Use the preceding thermochemical equations to find the enthalpy change when 50.0 g of water gas are burned in air.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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