9. Use the given plan to write a two-column proof of the Symmetric Property of Congruence. Given: AB = EF Prove: EF = AB F Plan: Use the definition of congruent segments to write AB = EF as a statement of equality. Then use the Symmetric Property of Equality to show that EF = AB. So EF = AB by the definition of congruent segments. %3D
9. Use the given plan to write a two-column proof of the Symmetric Property of Congruence. Given: AB = EF Prove: EF = AB F Plan: Use the definition of congruent segments to write AB = EF as a statement of equality. Then use the Symmetric Property of Equality to show that EF = AB. So EF = AB by the definition of congruent segments. %3D
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
100%
Number 9
Please make and fill out two column proof
![lon. Write a justification for each step.
2. 4y-1= 27
3.-중32
1. m-8= 13
Identify the property that justifies each statement.
4. MZXYZ == MZPQR, so mZPQR = mZXYZ.
6. 24 = LA, and ZA Z1. So 24 Z1.
5. AB = AB
7. k 7, and m = 7. So k = m.
2-6 Geometric Proof
8. Fill in the blanks to complete the two-column proof.
Given: mz1 + mZ3 = 180°
Prove: 21 4
Proof:
Statements
Reasons
1. m21 + mZ3 = 180°
1. a.
2. b.
2. Def. of supp. A
3. 23 and 24 are supplementary.
3. Lin. Pair Thm.
4. 23 = 23
4. С.
5. d.
5. = Supps. Thm.
9. Use the given plan to write a two-column proof of the Symmetric Property of
Congruence.
Given: AB = EF
Prove: EF = AB
A
F
Plan: Use the definition of congruent segments to write AB = EF as a statement
of equality. Then use the Symmetric Property of Equality to show that EF = AB.
So EF = AB by the definition of congruent segments.
Flowchart and Paragraph Proofs
the given two-column proof to write the following.
Given: Z1 Z3
Prove: 22 = L4
roof:
Statements
Reasons
21 23
1. Given
21 2, 23 4
22 쓴 13
2. Vert. Thm.
3. Trans. Prop. of =
22 쓴 24
4. Trans. Prop. of =
chart proof
11. a paragraph proof
Re](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc9c4f9a-526a-41e0-9d0f-ce9deae113de%2F22b8077f-6c06-4438-b9fd-021f6742105a%2Frw35vvh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:lon. Write a justification for each step.
2. 4y-1= 27
3.-중32
1. m-8= 13
Identify the property that justifies each statement.
4. MZXYZ == MZPQR, so mZPQR = mZXYZ.
6. 24 = LA, and ZA Z1. So 24 Z1.
5. AB = AB
7. k 7, and m = 7. So k = m.
2-6 Geometric Proof
8. Fill in the blanks to complete the two-column proof.
Given: mz1 + mZ3 = 180°
Prove: 21 4
Proof:
Statements
Reasons
1. m21 + mZ3 = 180°
1. a.
2. b.
2. Def. of supp. A
3. 23 and 24 are supplementary.
3. Lin. Pair Thm.
4. 23 = 23
4. С.
5. d.
5. = Supps. Thm.
9. Use the given plan to write a two-column proof of the Symmetric Property of
Congruence.
Given: AB = EF
Prove: EF = AB
A
F
Plan: Use the definition of congruent segments to write AB = EF as a statement
of equality. Then use the Symmetric Property of Equality to show that EF = AB.
So EF = AB by the definition of congruent segments.
Flowchart and Paragraph Proofs
the given two-column proof to write the following.
Given: Z1 Z3
Prove: 22 = L4
roof:
Statements
Reasons
21 23
1. Given
21 2, 23 4
22 쓴 13
2. Vert. Thm.
3. Trans. Prop. of =
22 쓴 24
4. Trans. Prop. of =
chart proof
11. a paragraph proof
Re
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)
Recommended textbooks for you
![Elementary Geometry For College Students, 7e](https://www.bartleby.com/isbn_cover_images/9781337614085/9781337614085_smallCoverImage.jpg)
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
![Elementary Geometry for College Students](https://www.bartleby.com/isbn_cover_images/9781285195698/9781285195698_smallCoverImage.gif)
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning
![Elementary Geometry For College Students, 7e](https://www.bartleby.com/isbn_cover_images/9781337614085/9781337614085_smallCoverImage.jpg)
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
![Elementary Geometry for College Students](https://www.bartleby.com/isbn_cover_images/9781285195698/9781285195698_smallCoverImage.gif)
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning