9. Three point-like charges are placed at the following points on the x-y system coordinates (q1 is fixed at x = -3.00 cm, q2 is fixed at y = +1.00 cm, and q3 is fixed at x = +1.00 cm. Find the electric potential energy of the charge q1. Let q1 = -3.20 µC, q; = +3.10 µC, and q3 = +3.70 µC. y(cm) +3 +2 +1 -1 -1 +2 +3 19.6of19 oof19 oof19 oof19 0of19.00, -2 19 0of19 oof199 ooft oof19 oof oof19 oof19 oof19 oof19 oof 9 oof19 o oof19 oof19
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- Two point charges Q1 = -2.00 nC and Q: = +4.00 nC are separated by 40.0 cm. (a) What is the potential energy of the pair? (b) What is the electric potential at a point midway between the charges?The figure shows a thin plastic rod of length L = 14.5 cm and uniform positive charge Q = 56.6 fC lying on an x axis. With V = 0 at infinity, find the electric potential at point P₁ on the axis, at distance d = 3.75 cm from one end of the rod. Number Units P₁ D P₂ -X1 - A charge q, = 2x10-6 C is located at the origin, and a charge q2 = -6x106 C is located at (0, 3) m, as shown in Figure. What is the total electric potential due to these charges at the point P, whose coordinates are (4, 0) m? -6.00 µC. 3.00 m 2.00 µC 4.00 m a) O 6.29 x 10³ v b) O -6.29 x 10³ V c) O 6.89 x 10³ V d) O -6.89 x 103 v e) O 6x 103 v
- A point charge Q1=+5.9 uC is fixed in space, while a point charge Q2=+2.2 nC, with mass 7.6 ug, is free to move nearby. A) calculate the electric potential energy of the system, in joules, when Q2 is located 0.42 m from Q1. B) if Q2 is released from rest at a point 0.42 m from Q1, what will be its speed, in meters per second, when it is 0.77m from Q1? 6. Four point-like charges are placed as shown in the figure, a = 20.0 cm and b = 56.0 cm. Find the electric potential energy of the entire system of charges. Let q₁ = -3.20 µC, q2 = +3.80 μC, 93 = -3.70 µC, and 94 = +7.90 µC. J On 940 b 93 92 COMConsider charges placed at the corners of a rectangle: The value of the Coulomb constant is 8.98755 x 10⁹ Nm2/C2 and the acceleration of gravity is 9.8 m/s². P -0.35 m 6 μC + 0.25 m -9 μC -12 μC Find the electric potential at point P due to the grouping of charges at the other corners of the rectangle. Answer in units of V.
- Three point charges Q1 = -2.2 uC, Q2 = -3.2 uC and Q3 = -0.6 uC are initially, infinitely far apart. They are then brought together and placed at the corners of an equilateral triangle. Each side has a length of 41 cm. Determine the total electric potential energy of these group of charges. Express your answer in mJ. show complete solution and express the answer in 4 decimal places if posssibleAn electron moving parallel to the x axis has an initial speed of 5.06 x 10° m/s at the origin. Its speed is reduced to 1.28 x 105 m/s at the point x = 2.00 cm. %3D (a) Calculate the electric potential difference between the origin and that point. Volts (b) Which point is at the higher potential? both have the same potential the point x = 2.00 cm the originTwo point charges, Q = +5.60 μC and q = −2.10 μC, are separated by 5.0 m. What is the electric potential energy?
- 9 a)What is the work done by the electric force? W= b)What is the potential of the starting point with respect to the end point? DeltaV= c)What is the magnitude of E⃗? |E⃗|=Points A, B and C are fixed at the vertices of an equilateral triangle whose edges are 3.00m long. A point charge of +2.0 μC is fixed at vertices A and vertices B.a) What is the electric potential at vertices C assuming V = 0 ar r = ∞?b) How much work is required to bring a +5.00 μC point charge from infinity to vertices C?c) How much additional work is needed to move the +5.00 μC point charge from vertices Cto the midpoint of side AB?Two point charges Q₁ = - -2.92 μC and Q2 = 2.52 µC are shown in the figure. Q₁ is located at (-2.1 cm, 0.0 cm) while Q2 is at (0.0 cm, — 2.6cm)). Use k = 9.0 × 10⁹ Nm²/C² (A) Find the electric potential at the origin. V = (B) If a -2.81 nC charge with a mass of 12.3 g is released from rest at the origin, how fast will it be moving when it is very far away from the charges? V = (C) If a proton is released from rest very far away from the charges shown above, how fast would it be moving at the origin? V =