9. The rigid horizontal bar ABC of negligible mass is connected to two rods as shown in the figure. If the system is initially stress-free, a temperature change will cause a tensile stress of 120 MPa in the brass rod. Assume that both rods are subjected to the same change in temperature. Brass L = 2 m A = 1200 mm² E = 100 GPa a = 18.7 × 10-6/°C B 3 m 2 m Сopper L = 3 m A = 1500 mm² E = 120 GPa a = 16.8 x 10–6/°C Calculate the stress in the copper bar (in MPa). * Your answer Calculate the axial deformation in the brass bar (in mm). *

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
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02:56:43
a = 16.8 × 10-6/°C
Calculate the stress in the copper bar (in
MPа). *
Your answer
Calculate the axial deformation in the brass
bar (in mm). *
Your answer
Calculate the axial deformation in the brass
bar (in mm). *
Your answer
Calculate the change in temperature.
Indicate increase or decrease in temperature.
Your answer
Transcribed Image Text:02:56:43 a = 16.8 × 10-6/°C Calculate the stress in the copper bar (in MPа). * Your answer Calculate the axial deformation in the brass bar (in mm). * Your answer Calculate the axial deformation in the brass bar (in mm). * Your answer Calculate the change in temperature. Indicate increase or decrease in temperature. Your answer
9. The rigid horizontal bar ABC of negligible
mass is connected to two rods as shown in
the figure. If the system is initially stress-free,
a temperature change will cause a tensile
stress of 120 MPa in the brass rod. Assume
that both rods are subjected to the same
change in temperature.
Brass
L = 2 m
A = 1200 mm²
E = 100 GPa
a = 18.7 × 10-6/°C
B
3 m
2 m
Copper
L = 3 m
A = 1500 mm²
E = 120 GPa
a = 16.8 × 10–6/°C
Calculate the stress in the copper bar (in
MPа). *
Your answer
Calculate the axial deformation in the brass
bar (in mm). *
Transcribed Image Text:9. The rigid horizontal bar ABC of negligible mass is connected to two rods as shown in the figure. If the system is initially stress-free, a temperature change will cause a tensile stress of 120 MPa in the brass rod. Assume that both rods are subjected to the same change in temperature. Brass L = 2 m A = 1200 mm² E = 100 GPa a = 18.7 × 10-6/°C B 3 m 2 m Copper L = 3 m A = 1500 mm² E = 120 GPa a = 16.8 × 10–6/°C Calculate the stress in the copper bar (in MPа). * Your answer Calculate the axial deformation in the brass bar (in mm). *
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