9. The motor c speed is 15 resist the mo

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Chapter1: Units, Trigonometry. And Vectors
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**Question 9:**

The motor of a boat develops 60 kW when the boat's speed is 15 km/h. With how much force does the water resist the motion of the boat?
Transcribed Image Text:**Question 9:** The motor of a boat develops 60 kW when the boat's speed is 15 km/h. With how much force does the water resist the motion of the boat?
**Physics Problem Example: Calculating Average Power Output**

**Problem Statement:**

11. A weightlifter raises a 70-kg barbell from the floor to a height of 2.2 m in 1.2 s. What was his average power output during the lift?

**Solution:**

To find the weightlifter's average power output, we need to determine the work done and the time over which it was done. Power is given by:

\[ \text{Power (P)} = \frac{\text{Work Done (W)}}{\text{Time (t)}} \]

**Step-by-Step Solution:**

1. **Calculate the Work Done:**

   Work done (W) against gravity is given by:

   \[ W = m \cdot g \cdot h \]

   Where:

   - \( m \) = mass of the barbell = 70 kg
   - \( g \) = acceleration due to gravity = 9.8 m/s²
   - \( h \) = height = 2.2 m

   Substituting the values:

   \[ W = 70 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 2.2 \, \text{m} \]
   \[ W = 70 \times 9.8 \times 2.2 \]
   \[ W = 1509.6 \, \text{J} (Joules) \]

2. **Calculate the Average Power:**

   Using the formula for power:

   \[ P = \frac{W}{t} \]
   
   Where:

   - \( W \) = 1509.6 J
   - \( t \) = time taken = 1.2 s

   Substituting the values:

   \[ P = \frac{1509.6 \, \text{J}}{1.2 \, \text{s}} \]
   \[ P = 1258 \, \text{W} (Watts) \]

Therefore, the weightlifter's average power output during the lift is 1258 W.
Transcribed Image Text:**Physics Problem Example: Calculating Average Power Output** **Problem Statement:** 11. A weightlifter raises a 70-kg barbell from the floor to a height of 2.2 m in 1.2 s. What was his average power output during the lift? **Solution:** To find the weightlifter's average power output, we need to determine the work done and the time over which it was done. Power is given by: \[ \text{Power (P)} = \frac{\text{Work Done (W)}}{\text{Time (t)}} \] **Step-by-Step Solution:** 1. **Calculate the Work Done:** Work done (W) against gravity is given by: \[ W = m \cdot g \cdot h \] Where: - \( m \) = mass of the barbell = 70 kg - \( g \) = acceleration due to gravity = 9.8 m/s² - \( h \) = height = 2.2 m Substituting the values: \[ W = 70 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 2.2 \, \text{m} \] \[ W = 70 \times 9.8 \times 2.2 \] \[ W = 1509.6 \, \text{J} (Joules) \] 2. **Calculate the Average Power:** Using the formula for power: \[ P = \frac{W}{t} \] Where: - \( W \) = 1509.6 J - \( t \) = time taken = 1.2 s Substituting the values: \[ P = \frac{1509.6 \, \text{J}}{1.2 \, \text{s}} \] \[ P = 1258 \, \text{W} (Watts) \] Therefore, the weightlifter's average power output during the lift is 1258 W.
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