**Problem:**The gas tank in a truck holds $14$ gallons. The truck uses gas at a rate of $\frac{2}{5}$ gallons per mile. The amount of gas left after $x$ miles is found by using the equation $y = -\frac{2}{5}x + 14$.1. Write the equation in function notation.2. Then find $f(50)$, $f(150)$, and $f(300)$.**Instructions:**- **Equation in Function Notation:**\[ f(x) = -\frac{2}{5}x + 14 \]- **Calculate the following:** - $f(50)$: \_\_\_\_\_\_\_\_\_\_\_\_ - $f(150)$: \_\_\_\_\_\_\_\_\_\_\_\_ - $f(300)$: \_\_\_\_\_\_\_\_\_\_\_\_

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9. The gas tank in a truck holds 14 gallons. The truck uses gas at a rate of gal/mi. The amount of gas left after x miles is Found by using y = -x + 14. Write the equation in function notation. Then find f(50), f(150), and f(300).

9. The gas tank in a truck holds 14 gallons. The truck uses gas at a rate of gal/mi. The amount of gas left after x miles is Found by using y = -x + 14. Write the equation in function notation. Then find f(50), f(150), and f(300).

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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**Problem:**

The gas tank in a truck holds $14$ gallons. The truck uses gas at a rate of $\frac{2}{5}$ gallons per mile. The amount of gas left after $x$ miles is found by using the equation $y = -\frac{2}{5}x + 14$.

1. Write the equation in function notation.
2. Then find $f(50)$, $f(150)$, and $f(300)$.

**Instructions:**

- **Equation in Function Notation:**

\[ f(x) = -\frac{2}{5}x + 14 \]

- **Calculate the following:**

- $f(50)$: \_\_\_\_\_\_\_\_\_\_\_\_
- $f(150)$: \_\_\_\_\_\_\_\_\_\_\_\_
- $f(300)$: \_\_\_\_\_\_\_\_\_\_\_\_

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