= 9. Test at the 94 percent level of significance the null hypothesis Ho: p = 0.665 versus the alternative hypothesis H₁:p> 0.665, where p is the population proportion, n = 734 is the sample size, and = 511 is the number of observed "successes". Let Q₁ p be the sample proportion, Q2 the z-statistic, and Q3= 1 if we reject the null hypothesis Ho, and 230 otherwise. Let Q=In(3+1Q1+2|Q2|+3|Q3]). Then T = 5 sin² (1002) satisfies:- (A) 0≤T<1.- (B) 1≤T<2.-(C) 2≤T<3.- (D) 3≤T<4. (E) 4 ≤ T ≤ 5.
= 9. Test at the 94 percent level of significance the null hypothesis Ho: p = 0.665 versus the alternative hypothesis H₁:p> 0.665, where p is the population proportion, n = 734 is the sample size, and = 511 is the number of observed "successes". Let Q₁ p be the sample proportion, Q2 the z-statistic, and Q3= 1 if we reject the null hypothesis Ho, and 230 otherwise. Let Q=In(3+1Q1+2|Q2|+3|Q3]). Then T = 5 sin² (1002) satisfies:- (A) 0≤T<1.- (B) 1≤T<2.-(C) 2≤T<3.- (D) 3≤T<4. (E) 4 ≤ T ≤ 5.
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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
Transcribed Image Text:9. Test at the 94 percent level of significance the null hypothesis Ho: p= 0.665 versus
the alternative hypothesis H₁:p> 0.665, where p is the population proportion, n = 734 is
the sample size, and = 511 is the number of observed "successes". Let Q₁ = p be the
sample proportion, Q2 the z-statistic, and Q3 = 1 if we reject the null hypothesis Ho, and
23 = 0 otherwise. Let Q=In(3+Q₁+2|Q21+3|Q31). Then T = 5 sin² (1000) satisfies:-
(A) 0≤T<1. (B) 1≤T<2.-(C) 2≤T<3.-(D) 3 ≤T<4. (E) 4 ≤ T ≤ 5.
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