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9. Solve the initial value problem ( D² – 4D + 4)y = 0 ; y(0) = 3 ; y'(0) = 4 a. y = 3e2x – 2xe2x b. y = 3e2x + 2xe2x c.y = -3e2x – 2xe2x d. y = -3e2x + 2xe2x

9. Solve the initial value problem ( D² – 4D + 4)y = 0 ; y(0) = 3 ; y'(0) = 4 a. y = 3e2x – 2xe2x b. y = 3e2x + 2xe2x c.y = -3e2x – 2xe2x d. y = -3e2x + 2xe2x

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Differential equation

9. Solve the initial value problem (D2 - 4D + 4)y = 0 ; y(0) = 3 ; y'(0) = 4 c. y = -3e2x – 2xe2x d. y = -3e2x + 2xe2x a. y = 3e2x – 2xe2x %3D b. y = 3e2x + 2xe2x
Transcribed Image Text:9. Solve the initial value problem (D2 - 4D + 4)y = 0 ; y(0) = 3 ; y'(0) = 4 c. y = -3e2x – 2xe2x d. y = -3e2x + 2xe2x a. y = 3e2x – 2xe2x %3D b. y = 3e2x + 2xe2x
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