9. Question from 8.5: The Normal Distribution Consider the following probability. P(Z < 1.18) (a) Make a sketch of the area under the standard normal curve corresponding to the probability. O -1.18 1.18 WebAssign Plot -1.18 1.18 (b) Find the value of the probability of the standard normal random variable Z corresponding to this area. (Round your answer to four decimal places.) P(Z < 1.18) =
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- Z denote a random variable following the standard normal distribution. Pr(Z>1.8) = ?Exercise 24 Let A and B be 2 events : P(A) : 1 and P(B') 1 Can A and B be mutually exclusive? Why?Assume that variable z has a standard normal distribution in the population. Use the table of the standard Normal Distribution (attached) to find the probability of a z value in each of the following intervals: (a) 0 to 1.65; (b) 1.95 to ∞; (c) -1.30 to 0; (d) -∞ to 1.00.
- Use the table of areas under the standard normal curve to find the probability that a z-score from the standard normal distribution will lie within the interval. (Round your answer to four decimal places.) z < 1.3Find the value of the probability of the standard normal variable Z corresponding to the shaded area under the standard normal curve. (Round your answer to four decimal places. You may need to use the appropriate table in the Appendix of Tables to answer this question.) P(0.9 < z < 1.61) = 0.9 1.61Assume that adults have IQ scores that are normally distributed with a mean of μ= 100 and a standard deviation σ = 20. Find the probability that a randomly selected adult has an IQ less than 120. Click to view page 1 of the table. Click to view page 2 of the table. The probability that a randomly selected a (Type an integer or decimal rounded to fo Standard Normal Table (Page 1) NEGATIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 02 .03 .04 .05 .06 .07 .08 .09 -3.50 and lower .0001 -3.4 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 0002 -3.3 .0005 .0005 .0005 .0004 .0004 .0004 0004 .0004 0004 .0003 -3.2 .0007 .0007 .0006 .0006 .0006 .0006 0006 .0005 .0005 0005 -31 0010 .0009 .0009 .0009 .0008 .0008 .0008 .0008 .0007 .0007 -3.0 .0013 0013 .0013 0012 .0012 .0011 .0011 .0011 0010 0010 -2.9 .0019 .0018 0018 .0017 .0016 .0016 0015 .0015 .0014 .0014 -2.8 .0026 .0025 .0024 .0023 .0023 .0022 .0021 .0021 .0020 0019 -2.7 .0035 .0034 .0033 .0032 .0031…
- show work, thumbs up for correct answerPhoton is a training device that is designed to improve a user's reaction time. Similar devices have been criticized for being too easy to master, but the makers of Photon say that their device is built to give most users room to improve. The makers say that even among professional athletes, the proportion, p, who can score the top ranking of "light speed" is less than 18%. A random sample of 115 professional athletes is chosen, and 15 score a ranking of "light speed" while using the device. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to support the claim that the proportion of all professional athletes who can score a ranking of "light speed" is less than 18%. (a) State the null hypothesis H, and the alternative hypothesis H, that you would use for the test. Oロ H: ロ=ロ ローロ (b) For your hypothesis test, you will use a Z-test. Find the values of np and n (1-p) to confirm that a Z-test can be used. (One…Use the table of areas under the standard normal curve to find the probability that a z-score from the standard normal distribution will lie within the interval. (Round your answer to four decimal places.) z < 1.6
- Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(z ≥ −1.60)= _______________Shade the corresponding area under the standard normal curve.The round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 5.1 mm. Round values to 4 decimal places when possible. The mean of this distribution is . The standard deviation is . The probability that the round off error for a jumper's distance is exactly 4.3 is P(x=4.3)=P(x=4.3)= . The probability that the round off error for the distance that a long jumper has jumped is between 1.5 and 2.5 mm is P(1.5<x<2.5)=P(1.5<x<2.5)= . The probability that the jump's round off error is greater than 1.22 is P(x>1.22)=P(x>1.22)= . P(x>1.8∣x>0.5)=P(x>1.8∣x>0.5)= . Find the 54th percentile. Find the maximum for the lower quarter.A null and alternative hypothesis are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. Ho: Ha: р = 0.8 p0.8 What type of test is being conducted in this problem? A. Left-tailed test B. Two-tailed test C. Right-tailed test