9.Question from 8.5: The Normal DistributionConsider the following probability.P(Z < 1.18)(a) Make a sketch of the area under the standard normal curve corresponding to the probability.- 1.181.18WebAssign Plot-1.18You may need to use the appropriate table in the Appendix of Tables to answer this question.1.18(b) Find the value of the probability of the standard normal random variable Z corresponding to this area. (Round your answer to four decimal places.)P(Z < 1.18) =

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Answered: 9. Question from 8.5: The Normal…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Z denote a random variable following the standard normal distribution. Pr(Z>1.8) = ?
Assume that variable z has a standard normal distribution in the population. Use the table of the standard Normal Distribution (attached) to find the probability of a z value in each of the following intervals: (a) 0 to 1.65; (b) 1.95 to ∞; (c) -1.30 to 0; (d) -∞ to 1.00.
Use the table of areas under the standard normal curve to find the probability that a z-score from the standard normal distribution will lie within the interval. (Round your answer to four decimal places.) z < 1.3
Find the value of the probability of the standard normal variable Z corresponding to the shaded area under the standard normal curve. (Round your answer to four decimal places. You may need to use the appropriate table in the Appendix of Tables to answer this question.) P(0.9 < z < 1.61) = 0.9 1.61
Assume that adults have IQ scores that are normally distributed with a mean of μ= 100 and a standard deviation σ = 20. Find the probability that a randomly selected adult has an IQ less than 120. Click to view page 1 of the table. Click to view page 2 of the table. The probability that a randomly selected a (Type an integer or decimal rounded to fo Standard Normal Table (Page 1) NEGATIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .00 .01 02 .03 .04 .05 .06 .07 .08 .09 -3.50 and lower .0001 -3.4 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 0002 -3.3 .0005 .0005 .0005 .0004 .0004 .0004 0004 .0004 0004 .0003 -3.2 .0007 .0007 .0006 .0006 .0006 .0006 0006 .0005 .0005 0005 -31 0010 .0009 .0009 .0009 .0008 .0008 .0008 .0008 .0007 .0007 -3.0 .0013 0013 .0013 0012 .0012 .0011 .0011 .0011 0010 0010 -2.9 .0019 .0018 0018 .0017 .0016 .0016 0015 .0015 .0014 .0014 -2.8 .0026 .0025 .0024 .0023 .0023 .0022 .0021 .0021 .0020 0019 -2.7 .0035 .0034 .0033 .0032 .0031…
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Photon is a training device that is designed to improve a user's reaction time. Similar devices have been criticized for being too easy to master, but the makers of Photon say that their device is built to give most users room to improve. The makers say that even among professional athletes, the proportion, p, who can score the top ranking of "light speed" is less than 18%. A random sample of 115 professional athletes is chosen, and 15 score a ranking of "light speed" while using the device. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.05 level of significance, to support the claim that the proportion of all professional athletes who can score a ranking of "light speed" is less than 18%. (a) State the null hypothesis H, and the alternative hypothesis H, that you would use for the test. Oロ H: ロ=ロローロ (b) For your hypothesis test, you will use a Z-test. Find the values of np and n (1-p) to confirm that a Z-test can be used. (One…
Use the table of areas under the standard normal curve to find the probability that a z-score from the standard normal distribution will lie within the interval. (Round your answer to four decimal places.) z < 1.6
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(z ≥ −1.60)= _______________Shade the corresponding area under the standard normal curve.
The round off errors when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 5.1 mm. Round values to 4 decimal places when possible. The mean of this distribution is . The standard deviation is . The probability that the round off error for a jumper's distance is exactly 4.3 is P(x=4.3)=P(x=4.3)= . The probability that the round off error for the distance that a long jumper has jumped is between 1.5 and 2.5 mm is P(1.5<x<2.5)=P(1.5<x<2.5)= . The probability that the jump's round off error is greater than 1.22 is P(x>1.22)=P(x>1.22)= . P(x>1.8∣x>0.5)=P(x>1.8∣x>0.5)= . Find the 54th percentile. Find the maximum for the lower quarter.
(a) The graph shows a Standard Normal Distribution. You are given 1 or 2 z-score(s) and need to shade the area (=probability) corresponding to: P(z > 1.2). Click on the "Shade" menu to select the shading option corresponding to the question [to the left, to the right, or between 2 values]. Then slide the arrow to the appropriate z-score. Shade: Left of a value Click and drag the arrows to adjust the values. -4 -3 -2 -1 2 4 -1.5 (b) Part 2: you are given an area (=probability), and you need to compute c, which is the z-score that corresponds to the statement: P( - c < z < c) (This is an inverse standard normal distribution problem. Use technology to compute c) The arrow can only be dragged to tick marks that are multiples of 0.1 So, round c to 1 decimal place, and then move the arrow to that rounded value. Click on the "Shade" menu to select the shading option corresponding to the question [to the left, to the right, or between 2 values]. (If the question is less c, choose Left of a…
A normal distribution has a mean of μ = 36 with σ = 4. What is the probability of randomly getting a score between 30 and 38? Group of answer choices 0.2583 0.3753 0.7417 0.6247

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