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9.- If I have a hard disk that physically has 500 cylinders, 8 surfaces and 19 sectors per track. In that disk I generate only one partition that will cover all the disk space. Considering that this partition is formatted with four sectors per block in addition to that the area of nodes-i will have space for 4096 nodes-i where each node-i measures 64 bytes. 1. If we use the i-node format which is 64 bytes long, where the block pointers are 16 bits (2 bytes), this would be quite a limited filesystem, explain why.

9.- If I have a hard disk that physically has 500 cylinders, 8 surfaces and 19 sectors per track. In that disk I generate only one partition that will cover all the disk space. Considering that this partition is formatted with four sectors per block in addition to that the area of nodes-i will have space for 4096 nodes-i where each node-i measures 64 bytes. 1. If we use the i-node format which is 64 bytes long, where the block pointers are 16 bits (2 bytes), this would be quite a limited filesystem, explain why.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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9.- If I have a hard disk that physically has 500 cylinders, 8 surfaces and 19 sectors per track. In that disk I generate only one partition that will cover all the disk space. Considering that this partition is formatted with four sectors per block in addition to that the area of nodes-i will have space for 4096 nodes-i where each node-i measures 64 bytes. 1. If we use the i-node format which is 64 bytes long, where the block pointers are 16 bits (2 bytes), this would be quite a limited filesystem, explain why.
Transcribed Image Text:9.- If I have a hard disk that physically has 500 cylinders, 8 surfaces and 19 sectors per track. In that disk I generate only one partition that will cover all the disk space. Considering that this partition is formatted with four sectors per block in addition to that the area of nodes-i will have space for 4096 nodes-i where each node-i measures 64 bytes. 1. If we use the i-node format which is 64 bytes long, where the block pointers are 16 bits (2 bytes), this would be quite a limited filesystem, explain why.
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