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9. Given a = (1, 2, — 3), b = (- 12, 13, 7) then a + 3b = b. (- 35, 41, 18) a. (-11, 15, 4) c. (3, 4, 1) 10. Given a = (1, 2, – 3), b = (– 12, 13, 7), the angle between a and b is: a. 74 b. 102° c. 9° d. 96° d. (0, 0, 0)

9. Given a = (1, 2, — 3), b = (- 12, 13, 7) then a + 3b = b. (- 35, 41, 18) a. (-11, 15, 4) c. (3, 4, 1) 10. Given a = (1, 2, – 3), b = (– 12, 13, 7), the angle between a and b is: a. 74 b. 102° c. 9° d. 96° d. (0, 0, 0)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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9. Given a = (1, 2, − 3), b = (– 12, 13, 7) then a + 3b = a. ( 11, 15, 4) b. (- 35, 41, 18) c. (3, 4, 1) 10. Given a = (1, 2, — 3), b = (- 12, 13, 7), the angle between a and b is: a. 74 b. 102° c. 9° d. 96° d. (0, 0, 0)
Transcribed Image Text:9. Given a = (1, 2, − 3), b = (– 12, 13, 7) then a + 3b = a. ( 11, 15, 4) b. (- 35, 41, 18) c. (3, 4, 1) 10. Given a = (1, 2, — 3), b = (- 12, 13, 7), the angle between a and b is: a. 74 b. 102° c. 9° d. 96° d. (0, 0, 0)
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