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9. Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there. f(x) = 2x² + 2x. (-2,4) The slope of the function's graph at (-2,4) is (Simplify your answer.) The equation for the tangent line through (-2,4) is y=

9. Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there. f(x) = 2x² + 2x. (-2,4) The slope of the function's graph at (-2,4) is (Simplify your answer.) The equation for the tangent line through (-2,4) is y=

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How do you do problem 9? Thanks!
9. Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there. f(x)=2x²+2x, (-2,4) The slope of the function's graph at (-2,4) is (Simplify your answer.) The equation for the tangent line through (-2,4) is y= 10. Find the first and second derivatives. dy dx d²y 4+² -4 y = 8x 6 X 11. Find y' by (a) applying the Product Rule and (b) multiplying the factors to produce a sum of simpler terms to differentia y=(6-x²) (x³ - 2x+3) = (6-x²) and v= = (x³ - 2x+3). a. Apply the Product Rule. Let u = (u) = (6-x²) ([ + (x³-2x+3)(
Transcribed Image Text:9. Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there. f(x)=2x²+2x, (-2,4) The slope of the function's graph at (-2,4) is (Simplify your answer.) The equation for the tangent line through (-2,4) is y= 10. Find the first and second derivatives. dy dx d²y 4+² -4 y = 8x 6 X 11. Find y' by (a) applying the Product Rule and (b) multiplying the factors to produce a sum of simpler terms to differentia y=(6-x²) (x³ - 2x+3) = (6-x²) and v= = (x³ - 2x+3). a. Apply the Product Rule. Let u = (u) = (6-x²) ([ + (x³-2x+3)(
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