9. f for 65° 5/(11x - 17)

Q: 1. ſ tan²2xsec*2x dx

A: Let, z=tan(2x)dz=sec2(2x)d(2x)dz=sec2(2x)(2)dxdz=2sec2(2x)dxsec2(2x)dx=dz2

Q: 9. 4 sec2 0 tan 0 d0 0,

A: The solution is given below

Q: How did you get the value for 7pi/3 when it's not in the unit circle?

A: Polar coordinates (2,-7π/3)

Q: what would t equal if  sin(t)=   (-sqrt(3))/2 ?

A: what would t equal if  sin(t)=   (-sqrt(3))/2  All the solution possible in the interval 0 to 2π.

Q: 2 (tan²x + 1)√sin2x.dx= (tan², 0

A: Find your answer below

Q: Use trigonometric substitution x = 3 sec 0, to evaluate 4xV4x2 – 9 dx . 2

A: The given integral,∫4x4x2-9dx

Q: 8. Perform the following operations: (a) (50 260°)(4 280°) = (b) (0.8 -10°)(3 230°)(-4 220°) = = (c)…

A: “Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: Solve for x: 60 60° 2x- 1 x+ 3 60°

A: guven:

Q: Find the value of x. 96° (2x+1)°

A: We know that the angle substended by an arc at the centre is twice the angle substended  at the…

Q: 2000=4002sin2(theta) / 64

A:

Q: (1 - e") = 2 sin ()e

A:

Q: d Find of tollowing functions. faa)= sin" (3%) "(3*) + loga (3²+2X-4)

A: Given: f(x)=sin-13x+log232+2x-4 we have to find the derivative of the given function. Use The Chain…

Q: 2. a. arctan(-1) b. tanV3 C. tan-

A: a)tan-1(-1)=-π4b)tan-1(3)=π3

Q: arc JK = (7x - 39)° and arc ML = 87°, find x. *

A:

Q: 8. (2x° – 3x) dx

A:

Q: Find cos . r (10,-√21) ? ㅁ Enter

A:

Q: Find the Amplitude and Midline y = (5 - 2sin t)/5

A: The objective of the question is to find the amplitude and midline of the given trigonometric…

Q: find S Sint est in detail?

A:

Q: Simplify: 3 (4x³y'z*)(16x'y^z*") (4x's ,5, 4 (1}° 18x'y¯z

A:

Q: A skier skied on a circular trail, starting at the position (2.5, 0) on the circle and ended at the…

A:

Q: Eind y Sor (sinx) fort dx

A: