9. Element X has two naturally occurring isotopes; 10x with a percent abundance of 85% and 12x with a percent of 15% abundance Which is the most likely average atomic mass for element X? A. 10.1 amu B. 11.9 amu C. 12.3 amu D. 22.0 amu 2

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**Question 9:**
Element X has two naturally occurring isotopes, \(^{10}\text{X}\) with a percent abundance of 85% and \(^{12}\text{X}\) with a percent abundance of 15%. Which is the most likely average atomic mass for element X?

- A. 10.1 amu
- B. 11.9 amu
- C. 12.3 amu
- D. 22.0 amu

*Explanation:*
To determine the most likely average atomic mass, use the formula:

\[
\text{Average atomic mass} = (\text{mass of } ^{10}\text{X} \times \text{abundance of } ^{10}\text{X}) + (\text{mass of } ^{12}\text{X} \times \text{abundance of } ^{12}\text{X})
\]

Convert the percentage abundances into decimal form before calculating.
Transcribed Image Text:**Question 9:** Element X has two naturally occurring isotopes, \(^{10}\text{X}\) with a percent abundance of 85% and \(^{12}\text{X}\) with a percent abundance of 15%. Which is the most likely average atomic mass for element X? - A. 10.1 amu - B. 11.9 amu - C. 12.3 amu - D. 22.0 amu *Explanation:* To determine the most likely average atomic mass, use the formula: \[ \text{Average atomic mass} = (\text{mass of } ^{10}\text{X} \times \text{abundance of } ^{10}\text{X}) + (\text{mass of } ^{12}\text{X} \times \text{abundance of } ^{12}\text{X}) \] Convert the percentage abundances into decimal form before calculating.
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