9. Determine the complexity of the following implementations of the algorithms for adding, multiplying, and transposing n X n matrices: for (i = 0; i < n; i++) for (j = 0;j < n; j++) a[i] [j] %3! b[i] [j] + c[i] [j]; %3D for (i = 0; i < n; i++) for (j = 0; j < n; j++) for (k = a[i] [j] = 0; k < n; k++) a[i] [j] += b[i] [k] * c[k] [jl; %3! %3D for (i = 0; i
9. Determine the complexity of the following implementations of the algorithms for adding, multiplying, and transposing n X n matrices: for (i = 0; i < n; i++) for (j = 0;j < n; j++) a[i] [j] %3! b[i] [j] + c[i] [j]; %3D for (i = 0; i < n; i++) for (j = 0; j < n; j++) for (k = a[i] [j] = 0; k < n; k++) a[i] [j] += b[i] [k] * c[k] [jl; %3! %3D for (i = 0; i
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Determind the complexity of the following implementations of the
![9. Determine the complexity of the following implementations of the algorithms for
adding, multiplying, and transposing n X n matrices:
for (i
0; i < n; i++)
%3D
for (j
= 0; j < n; j++)
a[i] [j]
b[i] [j] + c[i] [j];
%3!
for (i = 0; i < n; i++)
!3!
for (j
0; j < n; j++)
%3D
for (k
a[i] [j] = 0; k < n; k++)
%3D
a[i] [j] += b[i] [k] * c [k] [j];
for (i = 0; i < n
for (j
1; i++)
i+l; j < n; j++) {
%3D
a[i] [j];
tmp
a[i] [j] = a[j] [i] ;
a[j] [i]
}
!3!
tmp;
!3!](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1f406ace-6666-4c16-9c3d-0d0ae88343e0%2Fcbd227a8-1414-41b5-9863-297b48cfd310%2Fs6o4t88_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9. Determine the complexity of the following implementations of the algorithms for
adding, multiplying, and transposing n X n matrices:
for (i
0; i < n; i++)
%3D
for (j
= 0; j < n; j++)
a[i] [j]
b[i] [j] + c[i] [j];
%3!
for (i = 0; i < n; i++)
!3!
for (j
0; j < n; j++)
%3D
for (k
a[i] [j] = 0; k < n; k++)
%3D
a[i] [j] += b[i] [k] * c [k] [j];
for (i = 0; i < n
for (j
1; i++)
i+l; j < n; j++) {
%3D
a[i] [j];
tmp
a[i] [j] = a[j] [i] ;
a[j] [i]
}
!3!
tmp;
!3!
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