9. At a light bulb factory, 1728 light bulbs are ready to be packaged. A worker randomly pulls 60 light bulbs out and tests each one. Two light bulbs are found to be defective a. Based on the information given, what is best estimate for the number of defective light bulbs among the 1728 light bulbs? Explain your reasoning. your b. If the light bulbs are put in boxes with 144 light bulbs in each box (in 12 packages of 12), then approximately how many defective light bulbs would you expect to find in a box? Ex- plain your reasoning f marhlcs He

Q: 6.7 Find the unique number which is equal to its half plus 1.

A:

Q: 10

A: To simplify 35+710.

Q: 2. 3. 8. 5.

A:

Q: 14. 10 19

A: 14 Consider the sine angle property is, sinx=perpendicularhypotenuse

Q: 11. S 8a'da = %3D

A: This is a problem related to integration. Based on the general formula of integration we will solve…

Q: Analyze and sketch a graph of the function y=2-x-x'. а. b. 4 -2 2 6 10 12 -2- -6-

A: Solve the following

Q: 25. 1 | 1 1 + 1 - 1

A: Solution is done in step 2

Q: Question 15.22

A: We have to find value of test statistics.

Q: 8. arctan (-1)

A:

Q: 14.

A: I have used theorem for circle

Q: 14. 115"

A:

Q: 8 14

A:

Q: %3D 6.

A: Please see the explanation below

Q: 3,

A: Use 2 chords power theorem

Q: 9. 10. 12 x + 4 x+ 3 16 X- 3 Page 2 2

A:

Q: 9.2 2 15 5 3 16

A:

Q: 6. 6.

A: If two secants are drawn to a circle from one exterior point, then the product of the external…

Q: 6. arctan 1 3

A:

Q: z° 70 50

A:

Q: Match the given parametric equations with one of the parametric curves. x-3- sint, y = 5+ cost O A.

A: To sketch the given parametric equation :- x = 3 -sin t  and  y = 5+cos t

Q: 16. 15 11.3

A: We know that, cos(x)=adjacent/hypotenuse.

Q: 2. tox²Sc.

A:

Q: 12 10 6. X%=

A:

Q: 1. 12

A: We can use the concept of Pythagoras theorem to solve the given problem.

Q: 11. 6.

A: We have to find radius

Q: to.025.15 i

A: Given that  t0.025,15 = a

Q: 21

A: for triangle ADB, use the Pythagorean theorem  AB2=AD2+BD2 x2=42+BD2 x2-42=BD2 x2-16=BD2 BD2=x2-16

Q: 15 B X D 16

A:

Q: 6-1 t.

A:

Q: Number 16 1.1

A:

Q: 1 x21 = 28

A: We know  abc = a×c + bc