9. A tube of Chapstick (4 cm tall) is placed 15 cm in front of a diverging lens( Radius =20 cm) 1 x=0 a) Draw 3 ray diagrams on the above picture. b) What is the location of the image? c) What is the height of the image?
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- A cosmetic mirro is designed to magnifiy your face by a factor of 1.53 when your face is 16cm in front of it. a) what type of mirror is it? concave, plane, or convex b) describe the image formed 1. virtual or real 2. upright or inverted 3. reduced or magnified c) calculate the radius of the curvature of the mirror (in cm)e) The object is between F and optical center Image: 1. 2. 3. Principal axisA positive lens has a focal length of 6cm. An object is located 18cm from the lens. a. how far from the lens is the image? b. is the image real or virtual, upright or inverted? c. trace three rays frin tge top if the object to confirm your results.
- 2. An object is located 60.0 cm to the left of a concave mirror (with R = 30 cm). a) What is the focal length for this mirror? Include the correct sign (positive or negative). b) Use the mirror equation to find the location of the image. State whether the image is real or virtual. c) Use the magnification equation to find the magnification of the image. State whether the image upright or inverted, and magnified or diminished. d) Confirm your answer to part (b) by drawing a ray diagram on the figure to find where image is located (Use three rays). 13. A light ray enters the three-lens system parallel to the axis as shown. Using graphical raytrace rules, draw the trajectory of that ray through the system. If the height of the entering ray is 1, what is the exiting ray height? f₁=10 parallel to axis f₂=10 12 units units f3=21. A tree 20m high is located 40m from the converging lens of focal length 8.00cm A.)Calculate the height of the image of the tree B.) Describe the characteristics of the image
- An object is placed 50 cm from a convex lens of radius 60 cm. What are the characteristics of the image? A) virtual and upright B) real and inverted C) real and upright D) virtual and inverted An object is placed at a distance of 18.0 cm to the left of a thin converging lens of focal length 10.0 cm. Where does the image form? A) 22.5 cm to the right of the lens B) 22.5 cm to the left of the lens C) 8.0 cm to the right of the lens D) 6.4 cm to the right of the lens . What best describes the set of focal points of a thin convex lens? * A) one focal point located either in front of or behind the lens B) two focal points on opposite sides of the lens, each the same distance to the lens C) two focal points on the same side of the lens, with one point twice as far from the lens as the other point D) two focal points on opposite sides of the lens, with one point twice as far from the lens as the other…An object is 8.5 cm away from a thin convex lens with focal length of f1 = 3.1 cm. 8.0 cm away from the first convex lens is a second convex lens on the same optical axis with focal length of f2 = 2.1 cm. a) Draw a principal ray diagram for the optical system including the different focal lengths, image and object distances. b) Describe the nature (real or virtual) and orientation of the final image relative to the object. c) Calculate the position of the final image after the two lenses and its magnification.2. A meter stick is held length wise along the principle axis of a concave mirror. The focal length of the mirror is 40 cm the zero end of the meter stick is L=65 cm from the mirror, %3! Meter stick 100 cm L (A) What type of image (real or virtual) will be formed? Justify/explain. (2 points) (B) How long is the image of the meter stick? Show your work. (8 points)
- 3. A 15.0 cm tall object is place 60 cm from a concave mirror, which has a focal length of 35.0 cm. a. Draw a ray diagram to locate the image. (The principle axis is drawn for you below) Circle the Correct Answer b. Will it be Real or Virtual? Real Virtual c. Is the image upright or inverted? с. Upright Inverted d. Is it larger, smaller or the same size as the object? Smaller Same Larger e. Calculate exactly where the image be formed? IT f:35cm or 0.35m %3D do di h=15cm oro.15m %3D 60cm or O.60m do %3D | %3D 60em -11.8cm l0 cm h' %3D / di3D11.8cm 15cm h, = -2.95 %3D2. A converging mirror has a focal length of f = 18 cm. a. Where must an object be placed in order to form an image that is exactly the same height as the object? (Think about what the magnification for this situation is, and work from there). b. Would this object be real or virtual? Is it upright or inverted? C. Draw a ray diagram for this situation.4. Diverging Lens - Object Inside Focal Point An object with heigh 0.75cm is placed a distance of 2.5 cm in front of a thin diverging lens with focal length -15cm. A. What is the image position in cm? Please draw a ray diagram and use the lens equation to solve algebraically. B. What is the image height? C. What is the magnification? ↑ 1 1 do d₁ + = 1 m= hi ho di do Skill: Find an Image Using 3 Principle Rays in Ray Diagram Skill: Find an Image Using the Lens Equation