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9. A sample of a group 1 bromide weighing 2.000 g was converted to a gas at 504.0 °C and 1.000 atm pressure. The resulting vapor occupied a volume of 1238 mL. Identify the group 1 metal present in the compound. (3) R = 0.0821 (atm LK'mol") De

9. A sample of a group 1 bromide weighing 2.000 g was converted to a gas at 504.0 °C and 1.000 atm pressure. The resulting vapor occupied a volume of 1238 mL. Identify the group 1 metal present in the compound. (3) R = 0.0821 (atm LK'mol") De

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please workout this problem for me, an example of what would be best for me is the screenshot with a paper I dont really understand it typed out. Thank you so much!!!! :) I appreciate anyone who could do it for me.

In questions 9 and 10, assume the gas behaves ideally. 9. A sample of a group 1 bromide weighing 2.000 g was converted to a gas at 504.0 °C and 1.000 atm pressure. The resulting vapor occupied a volume of 1238 mL. Identify the group 1 metal present in the compound. (3) R = 0.0821 (atm LK'mol") Pon
Transcribed Image Text:In questions 9 and 10, assume the gas behaves ideally. 9. A sample of a group 1 bromide weighing 2.000 g was converted to a gas at 504.0 °C and 1.000 atm pressure. The resulting vapor occupied a volume of 1238 mL. Identify the group 1 metal present in the compound. (3) R = 0.0821 (atm LK'mol") Pon
boyle's dnw. Prussuse is inven sely Propstinal to Volume. V. PV= K. %3D (h01) (2.45) = Pz (2:25) %3D 1, 08 afm P,= 2.51 at m 65.0' - 0.0855 atm. 760 V, = 13.3 L V2 = ? V2 = (251) (13.3) (0.0855) V2 = 396.44 L
Transcribed Image Text:boyle's dnw. Prussuse is inven sely Propstinal to Volume. V. PV= K. %3D (h01) (2.45) = Pz (2:25) %3D 1, 08 afm P,= 2.51 at m 65.0' - 0.0855 atm. 760 V, = 13.3 L V2 = ? V2 = (251) (13.3) (0.0855) V2 = 396.44 L
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