Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:### Problem 9
A point moves along a curve with the acceleration function \(\mathbf{a}(t) = \langle 2, 6t, 12t^2 \rangle\). Find its position function \(\mathbf{r}(t)\) given that \(\mathbf{r}(0) = \langle 0, 1, -1 \rangle\) and \(\mathbf{v}(0) = \langle 1, 0, 0 \rangle\).
### Explanation:
- **\(\mathbf{a}(t)\): Acceleration Function**:
The acceleration vector is given as \(\langle 2, 6t, 12t^2 \rangle\). It represents the rate of change of the velocity function over time.
- **\(\mathbf{r}(0)\): Initial Position**:
The initial position vector is \(\langle 0, 1, -1 \rangle\). This is the position of the point at time \(t = 0\).
- **\(\mathbf{v}(0)\): Initial Velocity**:
The initial velocity vector is \(\langle 1, 0, 0 \rangle\). It indicates the velocity of the point at time \(t = 0\).
The goal is to derive the position function \(\mathbf{r}(t)\) by integrating the acceleration function to find the velocity function, and using the initial conditions to determine the constants of integration for the position function.
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