9. A binary ionic compound crystallizes in the cubic unit cell shown below. The anions (larger ST ol spheres) define the unit cell while four cations (smaller dark spheres) are located in tetrahedral holes within the unit cell. What is the formula for this ionic compound (M = cation, X= anion)? bifor biloe 200 b io a. MX b. M2X MX2 d. M2X3 с. e. MX4
9. A binary ionic compound crystallizes in the cubic unit cell shown below. The anions (larger ST ol spheres) define the unit cell while four cations (smaller dark spheres) are located in tetrahedral holes within the unit cell. What is the formula for this ionic compound (M = cation, X= anion)? bifor biloe 200 b io a. MX b. M2X MX2 d. M2X3 с. e. MX4
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Binary Ionic Compound Crystallization
#### Question 9:
A binary ionic compound crystallizes in the cubic unit cell shown below. The anions (larger spheres) define the unit cell while four cations (smaller dark spheres) are located in tetrahedral holes within the unit cell. What is the formula for this ionic compound (M = cation, X = anion)?
##### Options:
a. MX
b. M₂X
c. MX₂
d. M₂X₃
e. MX₄
#### Diagram Description:
The provided diagram illustrates a cubic unit cell with larger spheres representing anions positioned at the corners. Smaller dark spheres representing cations are situated within tetrahedral holes of the cubic unit cell. There are four cations located within the unit cell.
#### Explanation:
- The unit cell shown is a cubic unit cell.
- The larger spheres (representing anions, X) are placed at the corners of the cube.
- The smaller spheres (cations, M) are found in the tetrahedral holes.
By analyzing the structure:
- There are 8 corners, each corner shared by 8 unit cells. Thus, each corner contributes \(1/8\) of an anion to the unit cell: \( 8 \times \frac{1}{8} = 1 \) anion per unit cell.
- There are 4 cations within the unit cell.
Hence, the formula for the ionic compound is MX₄.
Correct Answer: e. MX₄](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc31825ca-e532-4346-8c67-c6f0bc8ad95c%2Ff87dcb7e-e554-4db2-8e9f-dc20b2f90c65%2Fxr3f1gj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Binary Ionic Compound Crystallization
#### Question 9:
A binary ionic compound crystallizes in the cubic unit cell shown below. The anions (larger spheres) define the unit cell while four cations (smaller dark spheres) are located in tetrahedral holes within the unit cell. What is the formula for this ionic compound (M = cation, X = anion)?
##### Options:
a. MX
b. M₂X
c. MX₂
d. M₂X₃
e. MX₄
#### Diagram Description:
The provided diagram illustrates a cubic unit cell with larger spheres representing anions positioned at the corners. Smaller dark spheres representing cations are situated within tetrahedral holes of the cubic unit cell. There are four cations located within the unit cell.
#### Explanation:
- The unit cell shown is a cubic unit cell.
- The larger spheres (representing anions, X) are placed at the corners of the cube.
- The smaller spheres (cations, M) are found in the tetrahedral holes.
By analyzing the structure:
- There are 8 corners, each corner shared by 8 unit cells. Thus, each corner contributes \(1/8\) of an anion to the unit cell: \( 8 \times \frac{1}{8} = 1 \) anion per unit cell.
- There are 4 cations within the unit cell.
Hence, the formula for the ionic compound is MX₄.
Correct Answer: e. MX₄
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