[9.] A 6.0 kg package in an Amazon sorting room slides 3.0 m down a plane inclined 60 degrees below the horizontal. The coefficient of kinetic friction between the package and the plane is k = 0.35. Calculate the work done on the package by (a) friction; (b) gravity; (c) the normal force. If the package starts with velocity v = 2.0 m/s, what is its final velocity?

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**Physics Problem on Inclined Planes**

**Problem Statement:**

A 6.0 kg package in an Amazon sorting room slides 3.0 m down a plane inclined 60 degrees below the horizontal. The coefficient of kinetic friction between the package and the plane is \( \mu_k = 0.35 \). Calculate the work done on the package by (a) friction; (b) gravity; (c) the normal force. If the package starts with velocity \( v = 2.0 \, \text{m/s} \), what is its final velocity?

**Solution Overview:**

To solve this problem, we'll break it down into several steps:

1. **Determine the Forces:**
   - Gravitational Force (Component along the incline).
   - Frictional Force.
   - Normal Force.

2. **Calculate the Work Done:**
   - By friction.
   - By gravity.
   - By the normal force.

3. **Apply Energy Principles:**
   - Use work-energy theorem to find the final velocity of the package.

### Detailed Steps:

**1. Gravitational Force (Component along the incline):**
   - The gravitational force acting down the incline is given by: 
     \[ F_{\text{gravity, parallel}} = mg \sin \theta \]
   - Where \( m = 6.0 \, \text{kg} \), \( g = 9.8 \, \text{m/s}^2 \), and \( \theta = 60^\circ \).

**2. Frictional Force:**
   - The frictional force acting up the incline is calculated as:
     \[ F_{\text{friction}} = \mu_k F_{\text{normal}} \]
   - Where \( F_{\text{normal}} = mg \cos \theta \).

**3. Work Calculation:**
   - **Work done by friction** \( W_{\text{friction}} \):
     \[ W_{\text{friction}} = F_{\text{friction}} \times d \times \cos 180^\circ \]
   - **Work done by gravity** \( W_{\text{gravity}} \):
     \[ W_{\text{gravity}} = F_{\text{gravity, parallel}} \times d \times \cos 0^\circ \]
   - **Work done by normal force** \( W_{\text{
Transcribed Image Text:**Physics Problem on Inclined Planes** **Problem Statement:** A 6.0 kg package in an Amazon sorting room slides 3.0 m down a plane inclined 60 degrees below the horizontal. The coefficient of kinetic friction between the package and the plane is \( \mu_k = 0.35 \). Calculate the work done on the package by (a) friction; (b) gravity; (c) the normal force. If the package starts with velocity \( v = 2.0 \, \text{m/s} \), what is its final velocity? **Solution Overview:** To solve this problem, we'll break it down into several steps: 1. **Determine the Forces:** - Gravitational Force (Component along the incline). - Frictional Force. - Normal Force. 2. **Calculate the Work Done:** - By friction. - By gravity. - By the normal force. 3. **Apply Energy Principles:** - Use work-energy theorem to find the final velocity of the package. ### Detailed Steps: **1. Gravitational Force (Component along the incline):** - The gravitational force acting down the incline is given by: \[ F_{\text{gravity, parallel}} = mg \sin \theta \] - Where \( m = 6.0 \, \text{kg} \), \( g = 9.8 \, \text{m/s}^2 \), and \( \theta = 60^\circ \). **2. Frictional Force:** - The frictional force acting up the incline is calculated as: \[ F_{\text{friction}} = \mu_k F_{\text{normal}} \] - Where \( F_{\text{normal}} = mg \cos \theta \). **3. Work Calculation:** - **Work done by friction** \( W_{\text{friction}} \): \[ W_{\text{friction}} = F_{\text{friction}} \times d \times \cos 180^\circ \] - **Work done by gravity** \( W_{\text{gravity}} \): \[ W_{\text{gravity}} = F_{\text{gravity, parallel}} \times d \times \cos 0^\circ \] - **Work done by normal force** \( W_{\text{
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