9. 7cm F E 22cm 40 cm NOT TO SCALE EFGHIJ is a solid metal prism of length 40 cm. The cross section EFG is a right-angled triangle. EF=7cm and EG-22 cm. Calculate the length FJ. FG²= Fe² + EG² 7²+222 533 FJ² = 46² + GJ FJ² = √√533² + 402 Fj² = 533 + 1600 FG= 462= FG 3 √533 FJ² = 2133 43 = √2133 F623.0868cm Answer FJ= * 46.1844 cm 46.21 cm [4]
9. 7cm F E 22cm 40 cm NOT TO SCALE EFGHIJ is a solid metal prism of length 40 cm. The cross section EFG is a right-angled triangle. EF=7cm and EG-22 cm. Calculate the length FJ. FG²= Fe² + EG² 7²+222 533 FJ² = 46² + GJ FJ² = √√533² + 402 Fj² = 533 + 1600 FG= 462= FG 3 √533 FJ² = 2133 43 = √2133 F623.0868cm Answer FJ= * 46.1844 cm 46.21 cm [4]
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter12: Quadratic Functions
Section: Chapter Questions
Problem 80CLR
Question
Is the solution correct?Why or why not?
![9.
7cm
F
E
22cm
40 cm
NOT TO
SCALE
EFGHIJ is a solid metal prism of length 40 cm.
The cross section EFG is a right-angled triangle.
EF=7cm and EG-22 cm.
Calculate the length FJ.
FG²= Fe² + EG²
7²+222
533
FJ² = 46² + GJ
FJ² = √√533² + 402
Fj² = 533 + 1600
FG=
462=
FG
3
√533
FJ² = 2133
43 =
√2133
F623.0868cm
Answer FJ=
* 46.1844 cm
46.21
cm [4]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe68930b7-6552-46b3-ab6f-1ff15a13eb9f%2Ffc77c05a-b202-4aaf-b307-5aa0904e76f4%2Fy06w08i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9.
7cm
F
E
22cm
40 cm
NOT TO
SCALE
EFGHIJ is a solid metal prism of length 40 cm.
The cross section EFG is a right-angled triangle.
EF=7cm and EG-22 cm.
Calculate the length FJ.
FG²= Fe² + EG²
7²+222
533
FJ² = 46² + GJ
FJ² = √√533² + 402
Fj² = 533 + 1600
FG=
462=
FG
3
√533
FJ² = 2133
43 =
√2133
F623.0868cm
Answer FJ=
* 46.1844 cm
46.21
cm [4]
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