9. [-/0.1 Points] DETAILS MY NOTES 0/4 Submissions A mixture of 0.1027 mol of H2O, 0.1254 mol of CH4, 0.02490 mol of CO, and 0.08245 mol of H2 is placed in a 1.0-L steel pressure vessel at 944 K. The following equilibrium is established: 1 H2O(g) + 1 CH4(9) 1 CO(g) + 3 H₂(9) At equilibrium 0.01383 mol of CO is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of H2O, CH4, CO, and H2. Peg(H2O) Peq(CH)= Peq(CO) = Peq(H2) = (b) Calculate Kp for this reaction. Kp =

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9. [-/0.1 Points]
DETAILS
MY NOTES
0/4 Submissions
A mixture of 0.1027 mol of H2O, 0.1254 mol of CH4, 0.02490 mol of CO, and 0.08245 mol of H2 is placed in a 1.0-L steel pressure vessel at 944 K. The following equilibrium is established:
1 H2O(g) + 1 CH4(9) 1 CO(g) + 3 H₂(9)
At equilibrium 0.01383 mol of CO is found in the reaction mixture.
(a) Calculate the equilibrium partial pressures of H2O, CH4, CO, and H2.
Peg(H2O)
Peq(CH)=
Peq(CO) =
Peq(H2) =
(b) Calculate Kp for this reaction.
Kp =
Transcribed Image Text:9. [-/0.1 Points] DETAILS MY NOTES 0/4 Submissions A mixture of 0.1027 mol of H2O, 0.1254 mol of CH4, 0.02490 mol of CO, and 0.08245 mol of H2 is placed in a 1.0-L steel pressure vessel at 944 K. The following equilibrium is established: 1 H2O(g) + 1 CH4(9) 1 CO(g) + 3 H₂(9) At equilibrium 0.01383 mol of CO is found in the reaction mixture. (a) Calculate the equilibrium partial pressures of H2O, CH4, CO, and H2. Peg(H2O) Peq(CH)= Peq(CO) = Peq(H2) = (b) Calculate Kp for this reaction. Kp =
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