9 What is the equation of the circle with a radius of 7 and center at (6, -5)? A (x + 6)² + (y – 5)2 = 49 %3D B (x - 6)2 + (y + 5)2 = 7 %3D (x + 6)2 + (y- 5)² = 7 D (x- 6)2 + (y + 5)2 = 49 10 A sector of a circle is shown. 1.19 in. 17 The central angle measures 17°, and the arc length is 1.19 inches. What is the radius of the sector? F 2.8 inches G 3.9 inches H 4.0 inches 8.0 inches

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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9 What is the equation of the circle with a radius of 7 and center at (6, -5)?
A (x + 6)2 + (y - 5)2 = 49
B (x – 6)2 + (y + 5)2 = 7
C (x + 6)2 + (y - 5)² = 7
D (x- 6)2 + (y + 5)2 = 49
10 A sector of a circle is shown.
1.19 in.
17°
?
The central angle measures 17°, and the arc length is 1.19 inches. What is the radius of the
sector?
2.8 inches
G
3.9 inches
H.
4.0 inches
8.0 inches
Transcribed Image Text:9 What is the equation of the circle with a radius of 7 and center at (6, -5)? A (x + 6)2 + (y - 5)2 = 49 B (x – 6)2 + (y + 5)2 = 7 C (x + 6)2 + (y - 5)² = 7 D (x- 6)2 + (y + 5)2 = 49 10 A sector of a circle is shown. 1.19 in. 17° ? The central angle measures 17°, and the arc length is 1.19 inches. What is the radius of the sector? 2.8 inches G 3.9 inches H. 4.0 inches 8.0 inches
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