9) track and her dog Patch always walks at the end of his 8 foot leash on the outside of the track. If the straight parts of the track are 35 yards long and the semicircular ends have a diameter of 10 yards on the inside of the track, how much farther does Patch walk than Erin on each complete loop of the track? (see diagram below) Erin walks her dog around a track that is 15 feet wide. Erin always walks in the middle of the (5fe 10 yes -35ydz

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Transcription for Educational Use:**

**Problem 9:**

Erin walks her dog around a track that is 15 feet wide. Erin always walks in the middle of the track and her dog, Patch, always walks at the end of his 8-foot leash on the outside of the track. If the straight parts of the track are 35 yards long and the semicircular ends have a diameter of 10 yards on the inside of the track, how much farther does Patch walk than Erin on each complete loop of the track? (see diagram below)

**Diagram Explanation:**

The diagram shows an oval track with straight and semicircular sections. The straight sections are labeled as 35 yards each. The width of the track is marked at 15 feet, and the diameter of the semicircular ends is indicated as 10 yards.
Transcribed Image Text:**Transcription for Educational Use:** **Problem 9:** Erin walks her dog around a track that is 15 feet wide. Erin always walks in the middle of the track and her dog, Patch, always walks at the end of his 8-foot leash on the outside of the track. If the straight parts of the track are 35 yards long and the semicircular ends have a diameter of 10 yards on the inside of the track, how much farther does Patch walk than Erin on each complete loop of the track? (see diagram below) **Diagram Explanation:** The diagram shows an oval track with straight and semicircular sections. The straight sections are labeled as 35 yards each. The width of the track is marked at 15 feet, and the diameter of the semicircular ends is indicated as 10 yards.
Expert Solution
Step 1

Convert width of the track into yards, as follows:

1 yd = 3 ft

Therefore, Width of the track =15 ft = (15/3) yds = 5 yds

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