+(321)89- The result of the operation + (321) s+ (AB2) ₁6 in octal is :16A- 64 3237 5603CF523561310t The Asoll table is atable made on:A-6 bitsC- 8 bits.B = 10 bitss- 7 bitsMoot Whuting Algowhims4- In the following algorithm portion, B. F, I, and I areIntegers. If & is 10 before the execution.first line, how much us s'after the execution oftheofthese 3 lines?I <-2 * E-4pI <3 * = 2 * FJ<= 15*1 + 21* F/3C. Jis 1A. J is -1Bo J US OD. Jis - 2. f2-let i be a Mariable.type Integer, containingthe value 19. That displays the followingportion of the algorithm:IfthenElsethenklrote (" that's bad!")Wrote (" It's good!")End IfA. This portion of the algorithon displays "It's OK! "Bo This portion of the algorithm grant's "That's bad!"This part of the algorithm does not display anything.algorithm displaysCa It's ok!"Thustheportion of"That's bad!

Since you have posted multiple questions, we will provide the solution only to the first 3 questions…

Answered: 9- The result of the operation + (321)…

9- The result of the operation + (321) as + (AB2) 16 in octal is t A- 6432 3+ 5603 CE 523 5613 10- The Asoll table is atable made on'. A = 6 bits C- 8 bits. B- 10 bits s- 7 bits.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

+(321)8
9- The result of the operation + (321) s
+ (AB2) ₁6 in octal is :
16
A- 64 32
37 5603
CF
523
5613
10t The Asoll table is atable made on:
A-6 bits
C- 8 bits.
B = 10 bits
s- 7 bitsMoot

Whuting Algowhims
4- In the following algorithm portion, B. F, I, and I are
Integers. If & is 10 before the execution.
first line, how much us s'after the execution of
the
of
these 3 lines?
I <-2 * E-4p
I <3 * = 2 * F
J<= 15*1 + 21* F/3
C. Jis 1
A. J is -1
Bo J US O
D. Jis - 2. f
2-let i be a Mariable.
type Integer, containing
the value 19. That displays the following
portion of the algorithm:
If
then
Else
then
klrote (" that's bad!")
Wrote (" It's good!")
End If
A. This portion of the algorithon displays "It's OK! "
Bo This portion of the algorithm grant's "That's bad!"
This part of the algorithm does not display anything.
algorithm displays
C
a It's ok!"
Thus
the
portion of
"That's bad!

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